A current I ampere flows through a metallic wire of resistance X Ω when a potential difference V volt is applied across its ends
A current I ampere flows through a metallic wire of resistance X Ω when a potential difference V volt is applied across its ends. Which of the following is the correct relation between X, I and V?
X Ω प्रतिरोध वाले एक धातु के तार के सिरों पर V वोल्ट का विभवांतर आरोपित करने पर I एंपियर धारा प्रवाहित होती है। निम्नलिखित में से X, I और V के बीच कौन-सा संबंध सही है?
Detailed Solution & Logic
X = V/I
English:
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According to Ohm's Law, the resistance $X$ of a metallic wire is the ratio of the potential difference $V$ across its ends to the current $I$ flowing through it.
X= V/I
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Here:
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$V$ = potential difference in volts
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$I$ = current in amperes
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$X$ = resistance in ohms (Ω)
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Extra fact:
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If the potential difference is 10 V and the current is 2 A, then the resistance of the wire is $X = \frac{10}{2} = 5\ \Omega$.
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Resistance is independent of current or voltage for an ohmic conductor at constant temperature.
Hindi:
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ओम का नियम (Ohm's Law) के अनुसार, किसी धातु के तार का प्रतिरोध $X$ उस पर लागू वोल्टेज $V$ और उसमें बहने वाले धारा $I$ का अनुपात है।
X= V/ I
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यहाँ:
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$V$ = वोल्टेज (वोल्ट में)
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$I$ = धारा (एम्पीयर में)
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$X$ = प्रतिरोध (ओम में)
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अतिरिक्त तथ्य:
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यदि वोल्टेज 10 V और धारा 2 A है, तो तार का प्रतिरोध $X = \frac{10}{2} = 5\ \Omega$ होगा।
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ओमिक चालक के लिए, प्रतिरोध तापमान स्थिर रहने पर धारा या वोल्टेज पर निर्भर नहीं करता।
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