An office has 108 tables and 132 chairs. If \(\frac{1}{6}\) of the tables and \(\frac{1}{4}\) of the chairs are broken how many people can work in the office if each person needs one table and one chair?
An office has 108 tables and 132 chairs. If \(\frac{1}{6}\) of the tables and \(\frac{1}{4}\) of the chairs are broken how many people can work in the office if each person needs one table and one chair?
एक कार्यालय में 108 मेज और 132 कुर्सियाँ हैं। यदि मेजों का 1/6 और कुर्सियों का 1/4 भाग टूट गया हो। यदि प्रत्येक व्यक्ति को एक मेज और एक कुर्सी की आवश्यकता हो तो कितने लोग कार्यालय में काम कर सकते हैं?
Detailed Solution & Logic
90
Total tables = 108
Broken tables = $\frac{1}{6} \times 108 = 18$
Usable tables = $108 - 18 = 90$
Total chairs = 132
Broken chairs = $\frac{1}{4} \times 132 = 33$
Usable chairs = $132 - 33 = 99$
Each person needs 1 table + 1 chair, so the number of people = minimum of (tables, chairs)
$\min(90, 99) = 90$
Final Answer: 90
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