Chetan travels from City A to City B.
Chetan travels from City A to City B. If Chetan drives his car at \(\frac{3}{4}\) of his normal speed, then he reaches City B 33 minutes late. Find the time(in minutes) that chetan would have taken to travel from City A to City B if he drove at his normal speed.
चेतन शहर A से शहर B तक यात्रा करता है।यदि चेतन अपनी सामान्य चाल की \(\frac{3}{4}\) चाल पर चलता है, तो वह शहर B तक 33 मिनट देरी से पहुंचता हैं। यदि चेतन अपनी कार सामान्य चाल से चलाता, तो शहर A से शहर B तक यात्रा करने में उसे कितना समय (मिनट में) लगता ?
Detailed Solution & Logic
99
Let the normal time = t minutes
At $ \dfrac{3}{4} $ of normal speed, time becomes $\dfrac{t}{3/4} = \dfrac{4t}{3} $
Given delay = 33 minutes
$ \dfrac{4t}{3} - t = 33 $
$ \dfrac{4t - 3t}{3} = 33 $
$ \dfrac{t}{3} = 33 $
t = 99
Answer: 99 minutes
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