If an angle is \(10^\circ\) more than twice its complement, what is the angle?
If an angle is \(10^\circ\) more than twice its complement, what is the angle?
यदि कोई कोण अपने पूरक कोण से दोगुने से $10^\circ$ अधिक है, तो वह कोण क्या होगा?
Detailed Solution & Logic
Correct Answer:
\(63^\circ, 33^\circ\)
Let the angle be $x^\circ$.
Its complement is $(90 - x)^\circ$.
According to the question, the angle is $10^\circ$ more than twice its complement.
So,
$x = 2(90 - x) + 10$
$x = 180 - 2x + 10$
$x = 190 - 2x$
$3x = 190$
$x = \frac{190}{3} = 63\frac{1}{3}^\circ$
Thus, the angle is approximately $63^\circ$.
Answer = $63^\circ, 33^\circ$.
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