Manoj travels from City A to City B.
Manoj travels from City A to City B. If Manoj drives his car at \(\frac{1}{5}\) of his normal speed. then he reaches City B 36 minutes late. Find the time (in minutes) that Manoj would have taken to travel from City A to City B if he drove at his normal speed.
मनोज शहर A से शहर B तक यात्रा करता है। यदि मनोज अपनी कार को अपनी सामान्य चाल की \(\frac{1}{5}\) चाल पर चलाता है, तो वह शहर B तक 36 मिनट देरी से पहुंचता है। यदि मनोज अपनी कार सामान्य चाल से चलता, तो शहर A से शहर B तक यात्रा करने में उसे कितना समय (मिनट में) लगता?
Detailed Solution & Logic
9
Let normal speed time = t minutes
At $ \frac{1}{5} $ of normal speed, time becomes 5t
Given delay = 36 minutes
5t - t = 36
4t = 36
t = 9
Answer: 9 minutes
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