“Out of two boys, the elder’s age is three times the younger’s age. 9 years ago, it was five times the younger’s age. Find the present age of each.”
“Out of two boys, the elder’s age is three times the younger’s age. 9 years ago, it was five times the younger’s age. Find the present age of each.”
दो लड़कों में से बड़े की उम्र छोटे की उम्र की तीन गुनी है। 9 साल पहले यह छोटे की उम्र की पाँच गुनी थी। प्रत्येक की वर्तमान उम्र ज्ञात कीजिए।
Detailed Solution & Logic
18 years, 54 years/ 18 वर्ष, 54 वर्ष
Solution:
Let the present age of the younger boy be x years.
Then the elder boy’s present age = 3x years.
9 years ago:
Younger’s age = x − 9
Elder’s age = 3x − 9
According to the question:
Elder’s age was 5 times the younger’s age:
$3x - 9 = 5(x - 9)$
Solve:
$3x - 9 = 5x - 45$
$45 - 9 = 5x - 3x$
$36 = 2x$
$x = 18$
So,
Younger’s present age = 18 years
Elder’s present age = $3x = 54$ years
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