The average of
The average of / औसत क्या होगा।
\(1^2, 2^2, 3^2, 4^2, 5^2, 6^2, 7^2, 8^2\) and \(9^2\) is:
Detailed Solution & Logic
\(31\frac{2}{3}\)
Numbers: $ 1^2,2^2,3^2,4^2,5^2,6^2,7^2,8^2,9^2 $
= 1,4,9,16,25,36,49,64,81
Sum = 1+4+9+16+25+36+49+64+81 = 285
Average = $ \frac{285}{9} $
$ = 31\frac{2}{3} $
Answer = $ 31\frac{2}{3} $
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