What is the smallest perfect square divisible by each of 6, 12 and 18?
What is the smallest perfect square divisible by each of 6, 12 and 18?
6, 12 और 18 में से प्रत्येक से विभाज्य सबसे छोटा पूर्ण वर्ग हैं?
Detailed Solution & Logic
Correct Answer:
36
First find LCM of $6, 12, 18$
$6 = 2 \times 3$
$12 = 2^2 \times 3$
$18 = 2 \times 3^2$
LCM $= 2^2 \times 3^2$
$= 4 \times 9$
$= 36$
Now check if $36$ is a perfect square:
$36 = 6^2$ ✔
So, the smallest perfect square divisible by all three numbers is 36.
Correct Answer: 36
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