Which of the following can be the value of ‘k’ so that the number 217924k is divisible by 6?

Options
a) 4
b) 6
c) 0
d) 2

Solution

As per question
Multiple of 6 = 2 x 3
A number divisible by 6 will also be divisible by 2 and 3
The last digit of the number divisible by 2 will be even number
The sum of the digits of a number which is divisible by 3 will be divisible by 3
Number which will be divided by 3 after
25 + K = 27
25 is 27 K = 27 – 25
K = 2

Answer: 2