Maths

A sum of Rs 73,500 is divided among A, B, C and D in the ratio 3 : 7 : 9 : 11, respectively, What is the sum of the shares of A and D? Options a) Rs. 34,300b) Rs. 39,200c) Rs. 24,500d) Rs. 29,400 Solution As per question Amount = 73500A : B :

The certain sum amounts to Rs 9,982.50 in $ 2\frac12$ years at 12% p.a., interest compounded 10-monthly. The sum (in Rs) is: Options a) 8500b) 7800c) 8000d) 7500 Solution As per question Interest rate per year = 12%Interest rate to 10 months = $ \frac {10 \times 12}{12}$ = 10%Time = $ 2 \frac12y$ = 30 months

The value of 3×7+5−6÷3−9+45÷5×4−45 is: Optionsa) 9b) 6c) 7d) 36 Solution As per question  3×7+5−6÷3−9+45÷5×4−45  3×7+5−2−9+9×4−45  21+5−2−9+36−45  26−2−9+36−45  62−47−9 62−56 6 Ans: 6

A certain sum amounts to Rs 13200 after 4 years and to Rs 16400 after 8 years at the same rate percent p.a. at simple interest. The simple interest (in Rs) on the same sum at 10% p.a. for 3 1/5 years will be : Options a) 4000b) 3200c) 2500d) 3500 Solution As per questionP = Principle

What is the least number added to 2483 so that it is completely divisible by 3, 4, 5 and 6? Options a) 37 b) 23c) 22d) 30 Solution As per question LCM of 3 , 4 , 5 , 6 = 60$ 2483 \div 60$Quotient = 41Remainder = 2360 – 23 = 37 Ans :

The value of $ \frac {33}{40} + \frac {1}{5} [\frac{4}{5} – \frac{1}{5} \times (\frac {7}{8} – \frac {5}{4})] – \frac {4}{5}$ is : Options a) $ \frac 15$b) $ \frac 14$c) $ \frac 17$d) $ \frac 13$ Solution As per question$ \frac {33}{40} + \frac {1}{5} [\frac{4}{5} – \frac{1}{5} \times (\frac {7}{8} – \frac {5}{4})] –

Two numbers are in the ratio 9 : 11. If their HCF is 23, then the difference of the two numbers is: Options a) 46b) 146c) 56d) 253 Solution As per question Two numbers are in the ratio a : b = 9 : 11HCF = 231st No. = 23 x 9 = 2072nd No.

A shopkeeper buy a table fan marked at Rs 2,600 on 18% discount He marked it for Rs 2,800 and allows a 15% discount. How much does he earn? Optionsa) Rs. 420b) Rs. 200c) Rs. 220d) Rs. 248 Solution As per questionCP = $ \frac {2600 \times 18}{100}$ = 468 Rs.= 2600 – 468 =

The perimeter of an equilateral triangle is $ 36\sqrt{3} $ cm. Find its height. Options: a) 10 cmb) 18 cmc) 9 cmd) 6 cm Solution: Perimeter of an equilateral triangle = 3 x sides =$ 36\sqrt{3} $side =$ 12\sqrt{3} $ Height of triangle is = $ \frac{\sqrt{3}}{2} \times $side=$ \frac{\sqrt{3}}{2} \times 12\sqrt{3}$= $ 6\sqrt3 \times

A train can cross a tunnel of length 600 m in 54 second, and it can cross a 350 m long bridge in 36 second. Which of the following statements is/are correct?(i) The speed of the train is 60 km/h. (ii) The length of the train is 150 m. Options a) Only statement (ii)b) Only