The value of 33/40+1/5[4/5−1/5×(7/8−5/4)]−4/5 is :

The value of $\frac {33}{40} + \frac {1}{5} [\frac{4}{5} - \frac{1}{5} \times (\frac {7}{8} - \frac {5}{4})] - \frac {4}{5}$ is :

Options
a) $\frac 15$
b) $\frac 14$
c) $\frac 17$
d) $\frac 13$

Solution

As per question
$\frac {33}{40} + \frac {1}{5} [\frac{4}{5} - \frac{1}{5} \times (\frac {7}{8} - \frac {5}{4})] - \frac {4}{5}$
$\frac {33}{40} + \frac {1}{5} [\frac{4}{5} - \frac{1}{5} \times (\frac {7 \times 1 - 5 \times 2} {8})] - \frac {4}{5}$
$\frac {33}{40} + \frac {1}{5} [\frac{4}{5} - \frac{1}{5} \times (\frac {7 - 10 } {8})] - \frac {4}{5}$
$\frac {33}{40} + \frac {1}{5} [\frac{4}{5} - \frac{1}{5} \times \frac {-3} {8}] - \frac {4}{5}$
$\frac {33}{40} + \frac {1}{5} [\frac{4}{5} + \frac{3}{40}] - \frac {4}{5}$
$\frac {33}{40} + \frac {1}{5} [\frac{4 \times 8 + 3 \times 1}{40}] - \frac {4}{5}$
$\frac {33}{40} + \frac {1}{5} [\frac{32 + 3}{40}] - \frac {4}{5}$
$\frac {33}{40} + \frac {1}{5} [\frac{35}{40}] - \frac {4}{5}$
$\frac {33}{40} + \frac {7}{40} - \frac {4}{5}$
$\frac {33 \times 1 + 7 \times 1 - 4 \times 8}{40}$
$\frac {33 + 7 - 32}{40}$
$\frac {40 - 32}{40}$
$\frac {8}{40}$
$\frac {1}{5}$