2 times the present age of X is 7 years less than 6 times the present age of Y.
2 times the present age of X is 7 years less than 6 times the present age of Y. At present,P is 2 times as old as X, and Y is 8 years younger than Q. If P is 50 years older than Q, then the present age (in years) of Y is:
X की वर्तमान आयु का 2 गुना, Y की वर्तमान आयु के 6 गुने से 7 वर्ष कम है। वर्तमान में, P की आयु X की आयु की 2 गुनी है, और Y, Q से 8 वर्ष छोटा है। यदि P, Q से 50 वर्ष बड़ा है, तो Y की वर्तमान आयु (वर्षों में) क्या है?
Detailed Solution & Logic
13
Let the present age of Y be $y$ years.
Then, present age of X:
$2X = 6Y - 7$
$2X = 6y - 7$
$X = \frac{6y - 7}{2}$
Present age of P:
$P = 2X$
$P = 2 \times \frac{6y - 7}{2}$
$P = 6y - 7$
Y is 8 years younger than Q:
$Q = y + 8$
Given, P is 50 years older than Q:
$P = Q + 50$
Substituting values:
$6y - 7 = y + 8 + 50$
$6y - 7 = y + 58$
$5y = 65$
$y = 13$
Therefore, the present age of Y is:
Answer = 13 years
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