A can do half of a piece of work in 10 days,
A can do half of a piece of work in 10 days, while B can do the same work in 25 days. Both of them worked together for 10 days, and the remaining work was completed by C alone in 5 days. In how many days will A, B and C together finish the work?
A एक कार्य के आधे भाग को 10 दिनों में पूरा कर सकता है, जबकि B उसी कार्य को 25 दिनों में पूरा कर सकता है। उन दोनों ने एक साथ मिलकर 10 दिनों तक कार्य किया, और शेष कार्य को अकेले C ने 5 दिनों में पूरा किया। A, B और C एक साथ मिलकर उस कार्य को कितने दिनों में पूरा कर लेंगे?
Detailed Solution & Logic
\(9\frac{1}{11}\)
A का 1 दिन का कार्य = $ \frac{1/2}{10} = \frac{1}{20} $
B का 1 दिन का कार्य = $ \frac{1}{25} $
A + B का 1 दिन का कार्य = $ \frac{1}{20} + \frac{1}{25} = \frac{9}{100} $
A + B द्वारा 10 दिनों में किया गया कार्य = $ 10 \times \frac{9}{100} = \frac{90}{100} = \frac{9}{10} $
शेष कार्य = $ 1 - \frac{9}{10} = \frac{1}{10} $
C का 1 दिन का कार्य = $ \frac{1/10}{5} = \frac{1}{50} $
A + B + C का 1 दिन का कार्य = $ \frac{1}{20} + \frac{1}{25} + \frac{1}{50} = \frac{10 + 8 + 4}{200} = \frac{22}{200} = \frac{11}{100} $
A + B + C द्वारा पूरा कार्य करने का समय = $\frac{1}{11/100} = \frac{100}{11} = 9\frac{1}{11} \text{ दिन} $
Answer: $ 9\frac{1}{11}$ दिन
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