A farmer wants to prepare 20 kg of fertiliser
A farmer wants to prepare 20 kg of fertiliser mixture containing 42% nitrogen by mixing two types of fertilisers, A and B. Fertiliser A contains 30% nitrogen, and fertiliser B contains 50% nitrogen. How many kilograms of each fertiliser should he mix?
एक किसान दो प्रकार के उर्वरकों A और B को मिलाकर 42% नाइट्रोजन युक्त 20 kg उर्वरक मिश्रण तैयार करना चाहता है। उर्वरक A में 30% नाइट्रोजन है और उर्वरक B में 50% नाइट्रोजन है। मिश्रण में प्रत्येक उर्वरक की मात्रा ज्ञात कीजिए।
Detailed Solution & Logic
8 kg of A, 12 kg of B/ A का 8 kg, B का 12 kg
Let the farmer use $x$ kg of Fertiliser A. Then Fertiliser B = $20 - x$ kg.
Step 1: Nitrogen content equation
Total nitrogen in the mixture = nitrogen from A + nitrogen from B
$0.30x + 0.50(20 - x) = 0.42 \times 20$
Step 2: Simplify
$0.30x + 10 - 0.50x = 8.4$
$-0.20x + 10 = 8.4$
$-0.20x = -1.6$
$x = 8$
Step 3: Amount of Fertiliser B
$20 - x = 20 - 8 = 12$
Answer: 8 kg of A, 12 kg of B
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