What smallest number should be added to 16809 so that the sum is completely divisible by 41?
What smallest number should be added to 16809 so that the sum is completely divisible by 41?
वह सबसे छोटी संख्या ज्ञात कीजिए, जिसे 16809 में जोड़ने पर प्राप्त योगफल 41 से पूर्णतः विभाज्य हो जाए।
Detailed Solution & Logic
Correct Answer:
1
We need the smallest number to add to 16809 so that the result is divisible by 41.
First find the remainder when 16809 is divided by 41:
$41 \times 410 = 16810$
So, $16809$ is $1$ less than $16810$.
Hence, remainder = $40$ (or equivalently, $-1$ modulo 41).
To make it divisible, we need to add:
$41 - 40 = 1$
Correct Answer: 1
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