Find the number when successively divided by 3, 5 and 7 leaves remainder 2, 1 and 3, respectively, and the last quotient is 3.
Find the number when successively divided by 3, 5 and 7 leaves remainder 2, 1 and 3, respectively, and the last quotient is 3.
वह संख्या ज्ञात कीजिए जिसे क्रमिक रूप से 3, 5 और 7 से विभाजित करने पर शेषफल क्रमशः 2, 1 और 3 बचता है, और अंतिम भागफल 3 है।
Detailed Solution & Logic
365
Solution / समाधान (Simple):
Let the final quotient = 3
Step 1: Reverse with divisor 7
Number = $7 \times 3 + 3 = 24$
Step 2: Reverse with divisor 5
Number = $5 \times 24 + 1 = 121$
Step 3: Reverse with divisor 3
Number = $3 \times 121 + 2 = 365$
Final Answer / अंतिम उत्तर: 365
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