Find the smallest number which, when divided by 36, 45, and 54,…
Find the smallest number which, when divided by 36, 45, and 54, leaves a remainder of 3 in each case.
वह सबसे छोटी संख्या ज्ञात कीजिए, जिसे 36, 45 तथा 54 से विभाजित करने पर प्रत्येक दशा में शेषफल 3 प्राप्त हो।
Detailed Solution & Logic
Correct Answer:
543
LCM of 36, 45 and 54:
$36=2^2\times3^2,\;45=3^2\times5,\;54=2\times3^3$
$\text{LCM}=2^2\times3^3\times5=540$
Required number =540+3=543.
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