Find the smallest cube number which is divisible by 72, 108 and 300?
Find the smallest cube number which is divisible by 72, 108 and 300?
वह छोटी से छोटी घन संख्या ज्ञात कीजिए, जो 72, 108 और 300 से विभाज्य हैं?
Detailed Solution & Logic
27000
Solution:
Find LCM of 72, 108, 300
Prime factors:
72 = $2^3 \times 3^2$
108 = $2^2 \times 3^3$
300 = $2^2 \times 3 \times 5^2$
LCM = $2^3 \times 3^3 \times 5^2$
To make it a perfect cube, powers must be multiples of 3:
- $2^3$ ✔️
- $3^3$ ✔️
- $5^2$ ❌ → need one more 5
So multiply by 5:
$= 2^3 \times 3^3 \times 5^3 = (2 \times 3 \times 5)^3 = 30^3$
$30^3 = 27000$
✅ Final Answer: 27000
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