A kitchen wall, measuring 4.5 m in length and 2.8 m in height,
A kitchen wall, measuring 4.5 m in length and 2.8 m in height, needs to be tiled. The tiles are rectangular, 30 cm $\times $20 cm. if an additional 8% of tiles are required to account for errors and cuts, how many tiles should be purchased?
एक रसोई की दीवार, जिसकी लंबाई 4.5 मीटर और ऊँचाई 2.8 मीटर है, पर टाइल लगाने की जरूरत है। टाइले आयताकार हैं, जिनका आकार 30 सेमी $\times $ 20 सेमी है। यदि त्रुटियों और कट-ऑफ के लिए अतिरिक्त 8% टाइलों की आवश्यकता है, तो कितनी टाइलें खरीदी जानी चाहिए?
Detailed Solution & Logic
227
Solution:
Area of the wall
$= 4.5 \times 2.8 = 12.6 \text{ m}^2$
Area of one tile
$= 30 \text{ cm} \times 20 \text{ cm} = 0.3 \text{ m} \times 0.2 \text{ m} = 0.06 \text{ m}^2$
Number of tiles required (without extra)
$= \frac{12.6}{0.06} = 210$
Including 8% extra tiles,
$= 210 \times 1.08 = 226.8$
Since tiles cannot be purchased in fractions, round up to 227.
Answer: 227
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