Find the value of \(79 – 10\times [2 + 3\times\{12 – 6 (6 – 5)\times 2\}\div 20]\)
Find the value of/ मान ज्ञात कीजिए।
\(79 – 10\times [2 + 3\times\{12 – 6 (6 – 5)\times 2\}\div 20]\)
Detailed Solution & Logic
59
Solution:
$79 - 10\times [2 + 3\times{12 - 6(6-5)\times2}\div20]$
First:
6-5=1
$6\times1\times2=12$
12-12=0
So,
$79-10\times[2+3\times0\div20]$
$=79-10\times2$
=79-20
=59
✅ Answer: 59 (Option 4)
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