Simplify : $4((\frac{6}{4})x^2 – 25 x + 12) – 6 (x^2 + 5x – 13). $
Simplify / निम्नलिखित को सरल कीजिए।:
$4((\frac{6}{4})x^2 – 25 x + 12) – 6 (x^2 + 5x – 13). $
Detailed Solution & Logic
- 130x + 126
Let’s simplify step by step:
Given expression:
$4\left(\frac{6}{4}x^2 - 25x + 12\right) - 6(x^2 + 5x - 13)$
Step 1: Simplify inside brackets
$\frac{6}{4}x^2 = \frac{3}{2}x^2$
So expression becomes:
$4\left(\frac{3}{2}x^2 - 25x + 12\right) - 6(x^2 + 5x - 13)$
Step 2: Multiply terms
First bracket:
$4 \times \frac{3}{2}x^2 = 6x^2$
$4 \times (-25x) = -100x$
$4 \times 12 = 48$
So:
$6x^2 - 100x + 48$
Second bracket:
$-6(x^2 + 5x - 13) = -6x^2 - 30x + 78$
Step 3: Combine like terms
$(6x^2 - 100x + 48) + (-6x^2 - 30x + 78)$
- $6x^2 - 6x^2 = 0$
- $-100x - 30x = -130x$
- $48 + 78 = 126$
Final Answer:
-130x + 126
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