In a constituency, 45% of the total number of voters are males and the rest are females.
In a constituency, 45% of the total number of voters are males and the rest are females. If 60% of the males are illiterate and 60% of the females are literate, then by what per cent is the number of illiterate females more than that of literate males? (Rounded off to 2 decimal places)
एक निर्वाचन क्षेत्र में कुल मतदाताओं में से 45% पुरुष हैं तथा शेष महिलाएँ हैं। यदि पुरुषों में से 60% निरक्षर हैं और महिलाओं में से 60% साक्षर हैं, तो निरक्षर महिलाओं की संख्या, साक्षर पुरुषों की संख्या से कितने प्रतिशत अधिक है? (उत्तर को दो दशमलव स्थान तक पूर्णांकित कीजिए।)
Detailed Solution & Logic
22.22%
Let the total number of voters be 100.
- Males = 45
- Females = 55
60% of males are illiterate, so literate males
= 40% of 45
$= \frac{40 \times 45}{100}$
= 18
60% of females are literate, so illiterate females
= 40% of 55
$= \frac{40 \times 55}{100}$
= 22
Required percentage
$= \frac{22-18}{18}\times100$
$= \frac{4}{18}\times100$
= 22.22%
Answer: 22.22%
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