The least multiple of 11, which leaves a remainder of 8, when divided by 5, 3, 18 and 20 is: 11 का सबसे छोटा गुणज कौन - सा है जिसे 5, 3, 18 और 20 से विभाजित करने पर शेषफल 8 बचता है?

The least multiple of 11, which leaves a remainder of 8, - Number System MCQ Solution

LCM (5,3,18,20)=180
N-8=180k
N=180k+8
$ 180k+8 \equiv 0 \pmod{11} $
$ 180 \equiv 4 \pmod{11} $
$ 4k+8 \equiv 0 \pmod{11} $
$ 4k \equiv 3 \pmod{11} $
k=9
$ N=180\times9+8=1628 $
Answer = 1628

The least multiple of 11, which leaves a remainder of 8,

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