Find the largest number which divides 436, 530, 624 and 718,
Find the largest number which divides 436, 530, 624 and 718, leaving 13 as the remainder in each case.
वह सबसे बड़ी संख्या ज्ञात कीजिए जिससे 436, 530, 624 और 718 को विभाजित करने पर प्रत्येक स्थिति में शेषफल 13 बचता है।
Detailed Solution & Logic
Correct Answer:
47
Required number = (436-13, 530-13, 624-13, 718-13) =
(423, 517, 611, 705)
517-423=94
611-517=94
705-611=94
(423, 94)
$ 423 = 94\times4 + 47 $
$ 94 = 47\times2 + 0 $
= 47
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