The radius of the base of a right circular cone is 9 cm and its slant height is 49 cm. Find the curved surface area of the cone.
The radius of the base of a right circular cone is 9 cm and its slant height is 49 cm. Find the curved surface area of the cone.
एक समवृत्तीय शंकु के आधार की त्रिज्या 9 सेमी तथा उसकी तिर्यक ऊँचाई 49 सेमी है। शंकु का वक्र पृष्ठीय क्षेत्रफल ज्ञात कीजिए|
Detailed Solution & Logic
$1386 \text {cm}^ 2 $
Curved surface area of a cone:
$\text{CSA}=\pi rl$
Given:
Radius $r=9$ cm
Slant height $l=49$ cm
$\text{CSA}=\pi \times 9 \times 49$
$=\frac{22}{7}\times9\times49$
$=22\times 9\times7$
$=1386 \text{cm}^2$
Answer: $1386\ text{cm}^2$
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