The smallest natural number which is divisible by 26, 8, 11 and 13 is:
The smallest natural number which is divisible by 26, 8, 11 and 13 is:
वह छोटी से छोटी प्राकृतिक संख्या ज्ञात कीजिए, जो 26, 8, 11, और 13 से विभाज्य हो।
Detailed Solution & Logic
1144
$ 26 = 2 \times 13 $
$ 8 = 2^3 $
11 = 11
13 = 13
LCM = $ 2^3 \times 11 \times 13 $
LCM = $ 8 \times 143 = 1144 $
Similar Practice Questions
What is the unit digit of the product of all the prime numbers
What is the unit digit of the product of all the prime numbers between 51...
The sum of two numbers is 56. Their difference is $\frac{1}{7}$ of their sum. Their LCM is :
The sum of two numbers is 56. Their difference is $\frac{1}{7}$ of their sum. Their...
Evaluate :
Evaluate / हल कीजिए : \(41 – [21 -\{11 -(15 – 6 \div 3\times 3)\}]\)
The square root of any prime number is:
The square root of any prime number is: किसी भी आभाज्य संख्या का वर्गमूल हैं।
A number when increased by 50%’,
एक संख्या में 50 % की वृद्धि करने पर 2580 प्राप्त होता है। वह संख्या________...
The product of two consecutive natural numbers is 702. The greater of the two numbers is:
The product of two consecutive natural numbers is 702. The greater of the two numbers...
Find the sum of all prime numbers between 50 and 80.
Find the sum of all prime numbers between 50 and 80. 50 और 80 के...