What is the smallest perfect square that is divisible by 6, 12, and 18?
What is the smallest perfect square that is divisible by 6, 12, and 18?
सबसे छोटा पूर्ण वर्ग, जो 6, 12 और 18 से विभाज्य है ?
Detailed Solution & Logic
Correct Answer:
36
Find the LCM of 6, 12, and 18:
Prime factors:
6 = $2 \times 3$
12 = $2^2 \times 3$
18 = $2 \times 3^2$
LCM = $2^2 \times 3^2 = 36$
Now, 36 is already a perfect square:
$36 = 6^2$
Final Answer: 36
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