Time Distance and Speed questions with answers, short tricks and solution for SSC CGL, CHSL, GD, Bank, UPSSSC PET, CUET and all Competitive Exams.

## Time Distance and Speed Questions for Competitive Exams

**Question 1 :** A man walking at the rate of 5 km/hr. crosses a bridge in 15 minutes. The length of the bridge (in metres) is :

(1) 600

(2) 750

(3) 1000

(4) 1250

###### Show Answer

Speed of the man = 5km/hr

= 5 x

= $ latex \dfrac{250}{3} $ m / min

Time taken to cross the bridge

= 15 minutes

Length of the bridge

= speed × time

= x15 m

=1250 m

**Question 2:** A train is moving with the speed of 180 km/hr. Its speed (in metres per second) is :

(1) 5

(2) 40

(3) 30

(4) 50

###### Show Answer

m/sec

= 50 m/sec

**Question 3:** A speed of 30.6 km/.hr is the same as

(1) 8.5 m/sec

(2) l0 m/sec

(3) 12 m/sec

(4) 15.5 m/sec

###### Show Answer

(1) 30.6 kmph

= 30.6 x

=8.5 m/sec

**Question 4:** A car travels at a speed of 60 km/hr and covers a particular distance in one hour. How long will it take for another car to cover the same distance at 40 km/hr ?

(1) hours

(2) 2 hours

(3) hours

(4) 1 hour

###### Show Answer

Distance = Speed × Time= 60 km.

Time taken at 40 kmph

=

= hours

**Question 5:** Gautam goes to office at a speed of 12 kmph and returns home at 10 kmph. His average speed is :

(1) 11 kmph

(2) 22 kmph

(3) 10.9 kmph

(4) 12.5 kmph

###### Show Answer

Here distances are same.

Average speed = kmph

=

= kmph

**Question 6:** A train is running at the speed of 116 km/hr. The distance covered by the train in meters in 18 seconds is:

(1) 900 metre

(2) 1160 metre

(3) 508 metre

(4) 580 metre

###### Show Answer

Speed of train = 116 kmph

116 m./sec

=

Required distance = Speed × Time

= x 18

=580 metre

**Question 7:** A train 300 metres long is running at a speed of 25 metres per second. It will cross a bridge of 200 metres in

(1) 5 seconds

(2) 10 seconds

(3) 20 seconds

(4) 25 seconds

###### Show Answer

In crossing the bridge, the train travels its own length plus the length of the bridge.

Total distance (length)

= 300 + 200 = 500 m.

Speed = 25m/sec.

The required time

= 500 ÷ 25 = 20 seconds

**Question 8:** A train travelling at a speed of 30 m/sec crosses a platform, 600 metres long, in 30 seconds. The length (in metres) of train is

(1) 120

(2) 150

(3) 200

(4) 300

###### Show Answer

Let the length of train be x

According to the question

x=300 m

**Question 9:** A train of length 500 feet crosses a platform of length 700 feet in 10 seconds. The speed of the train is

(1) 70 ft/second

(2) 85 ft/second

(3) 100 ft/second

(4) 120 ft/second

###### Show Answer

Speed of train

=

=$frac \dfrac{(500+700)}{10} $

=120 ft/second

**Question 10:** A train 270 m long running at a speed of 36 kmph will cross a bridge 180 m long at ** __**.

(1) 40 sec

(2) 45 sec

(3) 50 sec

(4) 35 sec

###### Show Answer

36 kmph =36x =10 m/sec

Required time = = 45 seconds

### Time Distance and Speed Questions for SSC CGL, CHSL

**Question 11:** The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet?

(1) 10 am

(2) 10 : 30 am

(3) 11 am

(4) 11 : 30 am

###### Show Answer

Distance travelled by first train in one hour = 60 × 1 = 60km

Therefore, distance between two train at 9 a.m. = 330 – 60 = 270 km

Now, Relative speed of two trains = 60 + 75 = 135 km/hr

Time of meeting of two trains= = 2 hrs.

Therefore, both the trains will meet at 9 + 2 = 11 A.M.

**Question 12:** Two men are standing on opposite ends of a bridge 1200 metres long. If they walk towards each other at the rate of 5m/minute and 10m/minute respectively, in how much time will they meet each other ?

(1) 60 minutes

(2) 80 minutes

(3) 85 minutes

(4) 90 minutes

###### Show Answer

Men are walking in opposite directions. Hence, they will cover the length of bridge at their relative speed.

Required time= = 80 minutes

**Question 13:** Two towns A and B are 500 km apart. A train starts at 8 AM from A towards B at a speed of 70 km/hr. At 10 AM, another train starts from B towards A at a speed of 110 km/hr. When will the two trains meet ?

(1) 1 PM

(2) 12 Noon

(3) 12.30 PM

(4) 1.30 PM

###### Show Answer

Let two trains meet after t hours when the train from town A leaves at 8 AM.

Distance covered in t hours at 70 kmph + Distance covered in(t – 2) hours at 110 kmph= 500km

70t + 110 (t – 2) = 500

t= 4 hours

Hence, the trains will meet at 12 Noon.

**Question 14:** A train running at the speed of 84 km/hr passes a man walking in opposite direction at the speed of 6 km/hr in 4 seconds. What is the length of train (in metre) ?

(1) 150

(2) 120

(3) 100

(4) 90

###### Show Answer

Relative speed = (84 + 6) = 90 kmph= 25 m/sec.

Length of train= Relative speed × Time = 25 × 4 = 100 metre

**Question 15:** By walking at of his usual speed, a man reaches his office 20 minutes later than his usual time. The usual time taken by him to reach his office is

(1) 75 minutes

(2) 60 minutes

(3) 40 minutes

(4) 30 minutes

###### Show Answer

of usual time = Usual time + 20 minutes

of usual time = 20 minutes

Usual time = 20 × 3= 60 minutes

**Question 16 :** The speed of a car is 54 km/hr. What is its speed in m/sec?

(1) 15 m/sec

(2) 19-44 m/sec

(3) 194.4 m/sec

(4) 150 m/sec

###### Show Answer

1 kmph = m/sec

54 kmph = x 54 = 15 m/sec

**Question 17 :** A car covers a certain distance in 25 hours. If it reduces the speed by th, the car covers 200 km less in that time. The speed of car is

(1) 60 km/hr

(2) 30 km/hr

(3) 40 km/hr

(4) 50 km/hr

###### Show Answer

Speed of car = x kmph.

Distance = Speed × Time = 25x km.

Case II,

Speed of car = kmph

Distance covered = x 25= 20x km

According to the question,

25x – 20x = 200

5x = 200

x = = 40 kmph

**Question 18 :** A train covers a distance of 3584 km in 2 days 8 hours. If it covers 1440 km on the first day and 1608 km on the second day, by how much does the average speed of the train for the remaining part of the journey differ from that for the entire journey ?

(1) 3 km/hour more

(2) 3 km/hour less

(3) 4 km/hour more

(4) 5 km/hour less

###### Show Answer

Remaining distance

= (3584 – 1440 – 1608) km

= 536 km.

This distance is covered at the rate of

= 67 kmph.

Average speed of whole journey =

$latex \dfrac{3584}{56} = 64 kmph

Required difference in speed

= (67 – 64) kmph i.e. = 3 kmph more

**Question 19:** A man goes from Mysore to Bangalore at a uniform speed of 40 km/hr and comes back to Mysore at a uniform speed of 60 km/hr. His average speed for the whole journey is

(1) 48 km/hr

(2) 50 km/hr

(3) 54 km/hr

(4) 55 km/hr

###### Show Answer

Average speed=

=

= 48 km/hr

**Question 20 :** On a journey across Kolkata, a taxi averages 50 km per hour for 50% of the distance, 40 km per hour for 40% of it and 20 km per hour for the remaining. Average speed (in km/hour) for the whole journey is :

(1) 42

(2) 40

(3) 35

(4) 45

###### Show Answer

Total distance = 100 km.

Total time =

= 1+1+

=

Average speed =100 x = 40 km/hour

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