मान ज्ञात कीजिए|

$ \frac {33}{40} + \frac {1}{5} \big[\frac {4}{5} – \frac{1}{5} \times(\frac {7}{8} -\frac{5}{4}) \big] – \frac {4}{5} $ का मान ज्ञात कीजिए|

Options:
a) $ \frac 13 $
b) $ \frac 17 $
c) $ \frac 15$
d) $ \frac 14$

SSC Constable GD Exam : Elementary Mathematics

Solution:

$ \frac{33}{40} +\frac{1}{5}\big[\frac{4}{5} -\frac{1}{5}\times(\frac{7-10}{8})\big]-\frac{4}{5} $
$ \frac{33}{40} +\frac{1}{5}\big[\frac{4}{5} -\frac{1}{5}\times- \frac{3}{8}\big]-\frac{4}{5} $

$ \frac{33}{40} +\frac{1}{5}\big[\frac{4}{5}+\frac{3}{40}\big] -\frac{4}{5} $
$ \frac{33}{40} +\frac{1}{5}\big[\frac{32+3}{40}\big] -\frac{4}{5} $
$ \frac{33}{40}+\frac{1}{5}\big[\frac{35}{40}\big]-\frac{4}{5} $

$ \frac{33}{40}+\frac{7}{40}-\frac{4}{5} $
$ \frac{33+7- 32}{40} =\frac{18}{40} = \frac{1}{5} $

Correct Answer: $ \frac{1}{5} $