Find the area of a square, one of whose diagonals is 4.8 m long.
Options
a) 12.5 m2
b) 10.5 m2
c) 9.5 m2
d) 11.52 m2
Solution
As per question
Let the one side of square is a
Diagonals (d) = 4.8 m
Formula :
d = $ \sqrt 2a $
4.8 = $ \sqrt 2a $
a = $ \frac {4.8}{ \sqrt 2}$
Area of square = a2
Area of square = $ (\frac {4.8}{ \sqrt 2})^2 $
Area of square =$ \frac {23.04}{2}$ = 11.52
Ans: d) 11.52 m2