Maths MCQs

Question: 25 percent of 20 percent of a number is equal to 250. What is the 35 percent of that number? Answer: 1750 Solution: 25 percent of 20 percent of a number x = 2500.25(0.2)x=25035 percent of the number =0.35×0.35x= (250x4x5x35)/100=5x2x5x35=1750

Question: Swapnil can build a sofa in 16 days. Working together with Revathi he can finish the work in 129/17 days. Find the number of days taken by Revathi to complete the work if she works alone. Answer: 4. 128/9 days Solution:building a sofa workdone = wSwapnil can do in 16 days = w=16ss=speed of

Question: Rs. 9000 is lent at the rate of 80 percent per annum on compound interest (compounded half yearly). what will be the compound interest of 12 months? Answer: Rs. 8640 Solution:interest= PXRXT/100Compound interest be x(9000(0.5)(0.8)+ 9000(1+0.5(0.8))(0.8)(0.5))/1003600+5040Rs 8640

Question: The product of two numbers is 720 and their Highest common factor is 4. What is the Least common multiplier of these numbers? Answer: 3. 180 Solution: product of two numbers= HCF X LCM720= 4 LCMLCM= 180

Question: IF 45 percent of X is equal to 15 percent of Y, then what is the value of X:Y? Answer: 4. 1:3 Solution: 0.45x=0.15y3x=yx:y=1:3

Question: A student scores 75% in a test and gets 30 marks more than another student who secured 60%. What is the maximum marks in the test? Answer: 200 Solution: x is total marks . Then equation becomes0.75x=0.6x +300.15 x=30x=200

Question: Both A and B sells their watch at the rate of Rs. 5000 per watch. A earned a profit of 25 percent while B incurred a loss of 10 percent. What is the ratio of cost prices of A and B? Answer: 2. 18:25 Solution:Creating equations 25 percent profit at a sell of 5000c.p

Question: If the length of a rectangle is increased by 14.28 percent, then by how much percentage its breadth should be reduced to keep the area same? Answer: 2. 12.5 percent Solutions:Area of rectangle be x. length be y. breadth be z. new breadth be z1.then x=yzx=(1.1428y)(z1)=yzz1=1/1.1428=0.875z1-1=0.125percentage= 12.5

Question: Marked price of a chair is Rs. 2000. After giving two successive discounts of 20 percent and x percent, the chair is sold for Rs. 1400. What is the value of x? Answer: 12.5 percent Solutions: bulding equation selling price after 1 st dsicount 2000-0.2(2000)=1600building equation after x discount1600-(0.01)x1600=1400200=0.01(x) 16001/8=12.5 percent

Question: If M:N=9:6, then what is the value of (M+N):(M-N)? Answer: 3. 5:1 Solution: (M+N):(M-N)Dividing it by N on denominator as well as numeratorM/N=x=9:6=3:2(M+N):(M-N)=(x+1)/(x-1)=2.5/.5=55:1