Find the area of a square, one of whose diagonals is 4.8 m long.

Find the area of a square, one of whose diagonals is 4.8 m long.

Options
a) 12.5 m²
b) 10.5 m²
c) 9.5 m²
d) 11.52 m²

Solution

As per question
Let the one side of square is a
Diagonals (d) = 4.8 m
Formula :
d = $\sqrt 2a$
4.8 = $\sqrt 2a$
a = $\frac {4.8}{ \sqrt 2}$
Area of square = a²
Area of square = $(\frac {4.8}{ \sqrt 2})^2$
Area of square = $\frac {23.04}{2}$ = 11.52

Ans: d) 11.52 m²