\(\frac{(2.3)^3 + 0.027}{(2.3)^2 – 0.69 +0.09}\) बराबर हैं?
What is the value of \(\frac{(2.3)^3 + 0.027}{(2.3)^2 – 0.69 +0.09}\)
\(\frac{(2.3)^3 + 0.027}{(2.3)^2 – 0.69 +0.09}\) बराबर हैं?
Detailed Solution & Logic
Correct Answer:
2.6
Evaluate:
$\frac{(2.3)^3 + 0.027}{(2.3)^2 - 0.69 + 0.09}$
Notice:
$0.027 = (0.3)^3$ and $0.09 = (0.3)^2$
So expression becomes:
$\frac{(2.3)^3 + (0.3)^3}{(2.3)^2 - (2.3)(0.3) + (0.3)^2}$
Use identity:
$\frac{a^3 + b^3}{a^2 - ab + b^2} = a + b$
Here $a = 2.3$, $b = 0.3$
So value =
$2.3 + 0.3 = 2.6$
✅ Final Answer: 2.6
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