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$\frac{(2.3)^3 + 0.027}{(2.3)^2 – 0.69 +0.09}$ बराबर हैं?

What is the value of $\frac{(2.3)^3 + 0.027}{(2.3)^2 – 0.69 +0.09}$
$\frac{(2.3)^3 + 0.027}{(2.3)^2 – 0.69 +0.09}$ बराबर हैं?

2.6 2.00 2.33 2.80

Detailed Solution & Logic

Correct Answer:

2.6

Evaluate:

$\frac{(2.3)^3 + 0.027}{(2.3)^2 - 0.69 + 0.09}$

Notice:
$0.027 = (0.3)^3$ and $0.09 = (0.3)^2$

So expression becomes:
$\frac{(2.3)^3 + (0.3)^3}{(2.3)^2 - (2.3)(0.3) + (0.3)^2}$

Use identity:
$\frac{a^3 + b^3}{a^2 - ab + b^2} = a + b$

Here $a = 2.3$, $b = 0.3$

So value =
$2.3 + 0.3 = 2.6$

✅ Final Answer: 2.6

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