The area of a trapezium is 330 cm\(^2\). If the lengths of its parallel sides are 24 cm and 20 cm, find the distance between the parallel sides.
The area of a trapezium is 330 cm\(^2\). If the lengths of its parallel sides are 24 cm and 20 cm, find the distance between the parallel sides.
एक समलंब चतुर्भुज का क्षेत्रफल 330 cm\(^2\) हैं। यदि इसकी समांतर भुजाओं की लंबाई 24 cm और 20cm है, तो समांतर भुजाओं के बीच की दूरी ज्ञात कीजिए।
Detailed Solution & Logic
Correct Answer:
15 cm
Given: Area = 330 cm\(^2\), a = 24 cm, b = 20 cm
Formula of trapezium area: Area = \(\frac{1}{2} \times (a+b) \times\) h
Substitute the values: 330 = \(\frac{1}{2} \times (24 + 20) \times\) h
330 = \(\frac{1}{2} \times 44 \times\) h
330 = \(22 \times\) h
Solve for h: h = \(\frac{330}{22} = 15 \text{ cm}\)
Answer: 15 cm
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