The curved surface area of a of a cylindrical rod is 9900 cm\(^2\). If the length of the rod is 82 cm, find the outer radius of the rod (in cm) correct to two decimal places. Take \(\pi = \frac{22}{7}\).
The curved surface area of a of a cylindrical rod is 9900 cm\(^2\). If the length of the rod is 82 cm, find the outer radius of the rod (in cm) correct to two decimal places. Take \(\pi = \frac{22}{7}\).
एक बेलनाकार छड़ का बाह्य वक्र पृष्ठीय क्षेत्रफल 9900 cm\(^2\) है। यदि छड़ की लंबाई 82 cm है, तो छड़ की बाह्य त्रिज्या (cm में) दशमलव के दो स्थानों तक दो स्थानों तक ज्ञात कीजिए। \(\pi = \frac{22}{7}\) लीजिए।
Detailed Solution & Logic
19.21
Given:
Curved Surface Area (CSA) = $ 9900 \text{ cm}^2 $
$ h = 82 \text{ cm}, \quad \pi = \frac{22}{7} $
Formula:
CSA = $ 2\pi $ r h
9900 = $ 2 \times \frac{22}{7} \times r \times 82 $
9900 = $ \frac{3608}{7} \times r $
r = $ \frac{9900 \times 7}{3608} $
r = $ \frac{69300}{3608} $
r 19.2073
Correct to two decimal places:
r 19.21 cm
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