Two boys are standing on the opposite ends of 540 meters long bridge.

Two boys are standing on the opposite ends of 540 meters long bridge. If they start walking towards each others at same time at the speed of 18 meters/minutes and 12 meters/minutes respectively, then in how much time they meet each other?

a) 18 minutes
b) 14 minutes
c) 26 minutes
d) 32 minutes

Ans : a) 18 minutes

SSC GD – 30/03/2024 Shift -1

Solution:

Step 1: Determine the relative speed.

The first boy’s speed: 18 meters/minute
The second boy’s speed: 12 meters/minute

Since they are walking towards each other, their relative speed is the sum of their individual speeds:
Relative speed = 18 + 12 = 30 meters/minute

Step 2: Calculate the time it takes for them to meet.

The distance between the boys is 540 meters. The time taken to cover this distance at a relative speed of 30 meters/minute is:

Time = $\frac{\text{Distance}}{\text{Relative Speed}}$ = $\frac{540}{30}$ = 18 minutes

So, the two boys will meet after 18 minutes.