What is the least number added to 2483 so that it is completely divisible by 3, 4, 5 and 6?

Options
a) 37
b) 23
c) 22
d) 30

Solution

As per question
LCM of 3 , 4 , 5 , 6 = 60
2483 \div 60
Quotient = 41
Remainder = 23
60 – 23 = 37

Ans : 37 to be added in 2483 so that it is completely divisible by 3, 4, 5 and 6.

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