What is the value of sec (t), if tan (t) = $ \frac{1}{3}$ ?
Options
a) $ \frac{ \sqrt3}{3}$
b) $ \frac{2 \sqrt2}{3}$
c) $ \frac{ \sqrt10}{3}$
d) $ \frac{ \sqrt10}{9}$
Solution
As per question
tan Q = $ \frac {BC}{AC} = \frac 13 $
(AB)2 = (AC)2 + (BC)2
(AB)2 = (3)2 + (1)2
(AB)2 = 9 + 1 = 10
AB = $ \sqrt 10 $
sec (t) = $ \frac {BC}{AC} = \frac { \sqrt 10}{3} $
Ans is ) $ \frac { \sqrt 10}{3} $