A solid metallic rectangular block of dimensions 112 cm × 44 cm × 25 cm is melted and recast into a cylinder of radius 35 cm. The curved surface area (in cm2) of the cylinder is: (Take π=22/7)

Options
a) 7260
b) 6600
c) 7040
d) 6160

Solutions

As per questions
Volume of cuboid = \L \times B \times H
Volume of cylinder = \pi r^2h
Curved surface area of the cylinder = 2\pi rh

L = 112
B = 44
H = 25
R = 35
H = ?

H = 112 x 44 x 25 = \frac{22}{7} \times 35 \times 35
H = 112 x 44 x 25 x 7 = 22 x 35 x 35
H = 32

Curved surface area of the cylinder = 2 \pi rh
= 2 \times \frac{22}{7} \times 35\times 32
= 44 x 160
= 7040

Ans: c) 7040

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