If a+ \frac1a = 12, then find the value of a^2+ \frac{1}{a^2}

Options
a) 142
b) 140
c) 146
d) 144

Solution

As per question
a+ \frac1a = 12
Square both side
(a+ \frac1a)^2 = (12)2
a^2+ \frac{1}{a^2}+ 2 \times a \times \frac1a = 144
a^2+ \frac{1}{a^2}+2 = 144
a^2+ \frac{1}{a^2} = 144 – 2
a^2+ \frac{1}{a^2} = 142

Answer: 142

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