Sequence and Series Maths Questions in English with Solution for competitive exams. Selected MCQ question answer from the previous year exam question paper is very useful for upcoming SSC, UPSSSC, Bank examinations.
Practice Set : Sequence and Series
Question 1: The next number of the sequence 3, 5, 9, 17, 33 ….. is :
(1) 65
(2) 60
(3) 50
(4) 49
Show Answer
Question 2: Find the missing number of the sequence : “ 3, 14, 25, 36, 47, ?”
(1) 1114
(2) 1111
(3) 1113
(4) None of these
Show Answer
Question 3: The next term of the sequence 1, 2, 5, 26, … is :
(1) 677
(2) 47
(3) 50
(4) 152
Show Answer
Question 4: The missing term in the sequence 0, 3, 8, 15, 24, ..,.., 48 is
(1) 35
(2) 30
(3) 36
(4) 39
Show Answer
Question 5: In the sequence of numbers 5,8, 15, 20, 29, 40, 53, one number is wrong. The wrong number is
(1) 15
(2) 20
(3) 29
(4) 40
Show Answer
Question 6: 1 + 2 + 3 + ….. + 49 + 50 + 49 +48 + …… + 3 + 2 + 1 is equal to
(1) 1250
(2) 2500
(3) 2525
(4) 5000
Show Answer
Question 7 : The next number in the sequence 2, 8, 18, 32, 50, …. is :
(1) 68
(2) 72
(3) 76
(4) 80
Show Answer
Question 8: Next term of the sequence 8, 12, 9, 13, 10, 14, ….., is
(1) 11
(2) 15
(3) 16
(4) 17
Show Answer
Question 9: The number of terms in the series 1 + 3 + 5 + 7 …+ 73 + 75 is
(1) 28
(2) 30
(3) 36
(4) 38
Show Answer
Answer: (4) 38
Question 10: In the sequence of number 0, 7, 26, 63, ……., 215, 342 the missing term is
(1) 115
(2) 124
(3) 125
(4) 135
Show Answer
Question 11: The sum (101 + 102 + 103 + ….+ 200) is equal to :
(1) 15000
(2) 15025
(3) 15050
(4) 25000
Show Answer
Question 12: Which term of the series 72, 63, 54, ……. is zero?
(1) 11th
(2) 10th
(3) 9th
(4) 8th
Show Answer
Question 13: The sum 9 + 16 + 25 + 36 + ….+ 100 is equal to :
(1) 350
(2) 380
(3) 400
(4) 420
Show Answer
Question 14 :What is the 507th term of the sequence 1, –1, 2, –2, 1, –1, 2, – 2, 1,….?
(1) –1
(2) 1
(3) –2
(4) 2
Show Answer
Question 15: If the 4th term of an arithmetic progression is 14 and the 12th term is 70, then the first term is :
(1) – 10
(2) – 7
(3) + 7
(4) + 10
Show Answer
Question 16: By adding the same constant to each of 31, 7, – 1 a geometric progression results. The common ratio is :
(1) 13
(2) 2 
(3) – 12
(4) None of these
Show Answer
Question 17: The sum of the first 8 terms of a geometric progression is 6560 and the common ratio is 3. The first term is
(1) 1
(2) 2
(3) 3
(4) 4
Show Answer
Question 18: How many terms of the series“1 + 2 + 3 ……” add upto 5050?
(1) 50
(2) 51
(3) 100
(4) 101
Show Answer
Question 19:The seventh term of the sequence 1, 3, 6, 10, ……… is :
(1) 20
(2) 26
(3) 28
(4) 32
Show Answer
Question 20 : If the 10th term of the sequence a, a – b, a –2b, a – 3b, … is 20 and the 20th term is 10, then the xth term of the series is
(1) 10 – x
(2) 20 – x
(3) 29 – x
(4) 30 – x
Show Answer
Thanks for attempt Sequence and Series questions practice set for the preparation of competitive exams.