Math Mock Test in English for online practice of Competitive Exams. Objective MCQs with answer and solution.
Results
#1. In a school having roll strength 286, the ratio of boys and girls is 8 : 5. If 22 more girls get admitted into the school, the ratio of boys and girls become
#2. If the selling price of 4 articles is equal to the cost price of 5 articles, the profit per cent is :
#3. If the square of the sum of two numbers is equal to 4 times of their product, then the ratio of these numbers is :
#4. The rate of simple interest per annum of bank being decreased from 5% to$ 3\frac12 $ % the annual income of a person from interest was less by Rs 105. The sum deposited at the bank was :
#5. A sum of Rs 3200 invested at 10% p.a. compounded quarterly amounts to Rs 3362. Compute the time period
#6. A sum of money becomes $ \frac76 $ of itself in 3 years at a certain rate of simple interest. The rate per annum is :
#7. At what rate percent per annum will the simple interest on a sum of money be $ \frac25 $ of the amount in 10 years ?
#8. Sunil completes a work in 4 days, whereas Dinesh completes the work in 6 days. Ramesh works $ 1\frac1 2 $ times as fast as Sunil. The three together can complete the work in :
#9. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.
LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013
#10. Two pipes A and B can separately fill a cistern in 60 minutes and 75 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is filled in 50 minutes. In how much time the third pipe alone can empty the cistern?
