Math Mock Test in English for online practice of Competitive Exams. Objective MCQs with answer and solution.
Results
#1. If a number x is 10% less than another number y and y is 10% more than 125, then x is equal to :
#2. A person buys 100 cups at Rs 10 each. On the way 10 cups are broken. He sells the remaining cups at Rs 11 each. His loss percent is :
#3. The ratio of cost price and selling price is 5 : 4, the loss percent is :
#4. What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7 ?
LCM of 9, 10 and 15 = 90
The multiple of 90 are also divisible by 9, 10 or 15.
21 × 90 = 1890 will be divisible by them.
Now, 1897 will be the number
that will give remainder 7.
Required number = 1936 – 1897 = 39
#5. Find the sum of the first five terms of the following series.$ \frac{1}{1\times4}+\frac{1}{4\times7}+\frac{1}{7\times10} $ +………+…….
#6. $ \dfrac{(2.3)^3+0.027}{(2.3)^2-0.69+0.09} $ is equal to
#7. In a class there are 30 boys and their average age is 17 years. When on one boy aged 18 years leaving the class and another joining, the average age becomes 16.9 years. The age of new boy is :
#8. A box contains 280 coins of denomination carrying 1 rupee, 50 paise and 25 paise. The values of each kind of the coins are in the ratio of 8 : 4 : 3. Then the number of 50 paise coins is :
#9. $ \frac{4.41\times0.16}{2.1\times 1.6 \times 0.21} $ is simplified to
#10. The number 96 – 11 when divided by 8 would leave a remainder of
