Math Mock Test in English : 1

Math Mock Test in English for online practice of Competitive Exams. Objective MCQs with answer and solution.

Results

#1. (49)¹⁵ – 1 is exactly divisible by

#2. The greatest among the following numbers $ (3)^\frac13, (2)^\frac12,1, (6)^\frac16 $ is

$(2)^\frac12$

$(6)^\frac16$

$(3)^\frac13$

#3. The least number that should be added to 2055, so that the sum is exactly divisible by 27 is :

#4. Three glasses are filled with a mixture of acid and water in equal volume. The ratios of acid and water are 2 : 3, 3 : 4 and 4 : 5 respectively. The contents of these glasses are poured in a large vessel. The ratio of acid and water in the large vessel is :

411 : 540

401 : 544

417 :564

407 : 560

#5. The value of $ {3 +\frac{3}{3+\frac{1}{3+\frac{1}{3}}}} $ is

$\frac{40}{11}$

$\frac{43}{11}$

$\frac{46}{11}$

$\frac{41}{11}$

#6. On selling 17 balls at Rs 720, there is a loss equal to the cost price of 5 balls. The cost price (in Rs) of a ball is

#7. The compound interest on a certain sum for 2 year at 10% per annum is Rs 525. The simple interest on the same sum for double the time at half the rate percent per annum is :

Rs 520

Rs 550

Rs 500

Rs 515

#8. If a person marks a product 25% above the cost price but allows 10% discount, then the percentage of profit is :

35 %

15 %

17.5 %

12. 5%

#9. In one litre of a mixture of alcohol and water, water is 30%. The amount of alcohol that must be added to the mixture so that the part of water in the mixture becomes 15% is :

1000 ml

700 ml

300 ml

900 ml

#10. What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7 ?

LCM of 9, 10 and 15 = 90
The multiple of 90 are also divisible by 9, 10 or 15.
21 × 90 = 1890 will be divisible by them.
Now, 1897 will be the number
that will give remainder 7.
Required number = 1936 – 1897 = 39