If the diagonals of a rhombus are 48 cm and 64 cm, then what is the perimeter of rhombus?

a) 120 cm
b) 75 cm
c) 225 cm
d) 160 cm

Ans : 160 cm

SSC Constable GD Exam paper- Maths – 22 Feb 2024

Step-by-Step Solution:

The diagonals of a rhombus bisect each other at right angles. If the diagonals are given, the sides of the rhombus can be calculated using the Pythagorean theorem.

Given : Length of diagonals: 48 cm and 64 cm.

Half of the diagonals:

  • Half of the first diagonal = \frac{48}{2} = 24  cm.
  • Half of the second diagonal = \frac{64}{2} = 32  cm.

Using the Pythagorean Theorem:
The side of the rhombus is the hypotenuse of a right triangle formed by half of the diagonals:
Side = \sqrt{(24^2 + 32^2)}
Side} = \sqrt{(576 + 1024)} = \sqrt{1600} = 40 cm

Perimeter of the rhombus:
Since all sides of a rhombus are equal, the perimeter is:
Perimeter = 4 x Side = 4 x 40 = 160 cm

Thus, the perimeter of the rhombus is 160 cm.

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