Quantitative Aptitude Questions with Answers and Solution for SSC CGL- Mock Test of Maths MCQs set for online practice of upcoming Competitive exams.
Subject : Quantitative Aptitude (Mathematics)
Medium : English
Level : SSC CGL
All type Questions with Solution
As per latest exam pattern and syllabus
Set of 25 Questions – New Questions practice Set in Every Attempt
Results
#1. The least number, which is to be added to the greatest number of 4 digits so that the sum may be divisible by 345 is :
#2. Divide Rs. 7500 among A, B and C such that A’s share to B’s share is in the ratio of 5 : 2 and B’s share to C’s share is in the ratio 7 : 13. How much will B receive?
#3. If a boy walks from his house to school at the rate of 4 km per hour, he reaches the school 10 minutes earlier than the scheduled time. However, if he walks at the rate of 3 km per hour, then he reaches 10 minutes late. Find the distance of his school from his house :
#4. (461 + 462 + 463) is divisible by
#5. The fourth proportional to 0.12, 0.21, 8 is :
#6. What is the average of the first six (positive) odd numbers each of which is divisible by 7?
#7. A bag contains Rs. 90 coins in the denominations of 50 paise, 25 paise and 10 paise. If coins of 50 paise, 25 paise and 10 paise are in the ratio of 2 : 3 : 5, then the number of 25 paise coins in the bag is
#8. By how much does $ 5\sqrt7-2\sqrt5 $ exceed $ 3\sqrt7-4\sqrt5 $ ?
#9. The cost price of 100 books is equal to the selling price of 60 books. The gain percentage/loss percentage is :
#10. The list price of a clock is Rs 160. A customer buys it for Rs 122.40 after two successive discounts. If first discount is 10%, the second is ?
#11. Water tax is increased by 20% but its consumption is decreased by 20%. Then the increase or decrease in the expenditure of the money is :
#12. Two trains start at the same time from Aligarh and Delhi and proceed towards each other at the rate of 14 km and 21 km per hour respectively. When they meet, it is found that one train has travelled 70 km more than the other. The distance between the two stations is :
#13. A person who pays income tax at the rate of 4 paise per rupee, find that a fall of interest rate from 4% to 3.75% diminishes his net yearly income by Rs 48. What is his capital?
#14. Of the 1000 inhabitants in a town 60% are males of whom 20% are literate. If from all the in-habitants, 25% are literate, then what percentage of the females of the town is literate?
#15. 31% of employees pay tax in the year 2008. The number of non-tax paying employees are 20,700. The total number of employees is :
#16. Which of the following is the largest fraction?
$ \frac67, \frac56, \frac78, \frac45 $
#17. The middle term(s) of the following series 2 + 4 + 6 + … + 198 is
#18. Sourav purchased 30 kg of rice at the rate of Rs 10 per kg and 35 kg at the rate of Rs 11 per kg. He mixed the two. At what price per kg (in Rs) should he sell the mixture to make a 30% profit in the transaction?
#19. The average of five numbers is 7. When three new numbers are included, the average of the eight numbers becomes 8.5. The average of three new numbers is :
#20. What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7 ?
LCM of 9, 10 and 15 = 90
The multiple of 90 are also divisible by 9, 10 or 15.
21 × 90 = 1890 will be divisible by them.
Now, 1897 will be the number
that will give remainder 7.
Required number = 1936 – 1897 = 39
#21. A, B and C can do a piece of work in 30, 20 and 10 days respectively. A is assisted by B on one day and by C on the next day, alternately. How long would the work take to finish?
#22. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.
LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013
#23. A store has an offer ‘Buy 4 Get 1 Free’. What is the net percentage of discount?
#24. The Government reduced the price of sugar by 10 per cent. By this a consumer can buy 6.2 kg more sugar for Rs 837. The reduced price per kg of sugar is :
#25. A tank can be filled by pipe A in 2 hours and pipe B in 6 hours. At 10 a.m., the pipe A was opened. At what time will the tank be filled if pipe B is opened at 11 a.m.?
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