Quantitative Aptitude Questions with Answers for SSC CGL

Quantitative Aptitude Questions with Answers and Solution for SSC CGL- Mock Test of Maths MCQs set for online practice of upcoming Competitive exams.

Subject : Quantitative Aptitude (Mathematics)
Medium : English
Level : SSC CGL
All type Questions with Solution
As per latest exam pattern and syllabus
Set of 25 Questions – New Questions practice Set in Every Attempt

 

Results

#1. The cost price of 36 books is equal to the selling price of 30 books. The gain percent is :

#2. The greatest value among the fractions $ \frac27, \frac13,\frac56, \frac34 $

#3. If x : y = 3 : 4 and y : z = 3 : 4, then $ \frac {x+y+z} {3z} $ is equal to :

#4. Two places P and Q are 162 km apart. A train leaves P for Q and simultaneously another train leaves Q for P. They meet at the end of 6 hours. If the former train travels 8 km/hour faster than the other, then speed of train from Q is :

#5. The missing number of the sequence 0, 2, 8, 18,__, 50 is :

#6. In an examination there are three subjects of 100 marks each. A student scores 60% in the first subject and 80% in the second subject. He scored 70% in aggregate. His percentage of marks in the third subject is :

#7. A man bought an old type writer for Rs 1200 and spent Rs 200 on its repair. He sold it for Rs 1680. His profit per cent is :

#8. Two types of tea costing Rs 180 per kg and Rs 280 per kg should be mixed in the ratio so that the mixture obtained was sold at Rs 320 per kg to earn a profit of 20% is

#9. The average of 30 numbers is 12. The average of the first 20 of them is 11 and that of the next 9 is 10. The last number is :

Explanation: Last number :

= 30 × 12-20 × 11 − 9 × 10
= 360 − 220 − 90
= 360 − 310 = 50

#10. Six numbers are arranged in decreasing order. The average of the first five numbers is 30 and the average of the last five numbers is 25. The difference of the first and the last numbers is :

#11. The value of $ {3 +\frac{3}{3+\frac{1}{3+\frac{1}{3}}}} $ is

#12. The mean of 20 items is 55. If two items such as 45 and 30 are removed, the new mean of the remaining items is :

#13. Between two consecutive years my income are in the ratio of 2 : 3 and expenses are in the ratio of 5 : 9. If my income in the second year is `45,000 and my expenses in the first year is ` 25,000 my total savings for the two years is :

#14. The average age of 40 students of a class is 15 years. When 10 new students are admitted, the average is increased by 0.2 year. The average age of the new students is :

#15. If a boy walks from his house to school at the rate of 4 km per hour, he reaches the school 10 minutes earlier than the scheduled time. However, if he walks at the rate of 3 km per hour, then he reaches 10 minutes late. Find the distance of his school from his house :

#16. Three numbers are in the ratio 1 : 2 : 3. By adding 5 to each of them, the new numbers are in the ratio 2 : 3 : 4. The numbers are:

#17. What is the average of the first six (positive) odd numbers each of which is divisible by 7?

#18. . If x : y = 3 : 4, then 4x + 5y : 5x− 2y = ?

#19. LCM of 12 and 16 Prime factorisation of $ 12 = 2^3 $ × 3 = 22 × 3 Prime factorisation of 16 = 2 × 2 × 2 × 2 = 24

[la​tex]e^{i pi} 1 = 0[/lat​ex]

[la​tex]e^{i pi} 1 = 0[/lat​ex]

[la​tex]e^{i pi} 1 = 0[/lat​ex]

#20. A and B can together finish a work in 30 days. They worked at it for 20 days and then B left. The remaining work was done by A alone in 20 more days A alone can finish the work in :

#21. The present worth of a bill due 7 months hence is Rs 1200 and if the bill were due at the end of $ 2\frac12 $ years its present worth would be Rs 1016. The rate percent is :

#22. A shopkeeper allows a discount of 10% on the marked price of a camera. Marked price of the camera, which costs him Rs 600, to make a profit of 20% should be :

#23. Of the three numbers whose average is 60, the first is one fourth of the sum of the others. The first number is :

#24. The greatest number, by which 1657 and 2037 are divided to give remainders 6 and 5 respectively, is

The largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by HCF of (a – p), (b – q) and (c – r)
Required number
We have to find HCF of
(1657 – 6 = 1651) and (2037 – 5 = 2032)
1651 = 13 × 127, 2032 = 16 × 127
HCF = 127 So, required number will be 127

#25. Two pipes A and B can separately fill a tank in 2 hours and 3 hours respectively. If both the pipes are opened simultaneously in the empty tank, then the tank will be filled in :

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