Quantitative Aptitude Questions with Answers and Solution for SSC CGL- Mock Test of Maths MCQs set for online practice of upcoming Competitive exams.
Subject : Quantitative Aptitude (Mathematics)
Medium : English
Level : SSC CGL
All type Questions with Solution
As per latest exam pattern and syllabus
Set of 25 Questions – New Questions practice Set in Every Attempt
Results
#1. When a particular number is subtracted from each of 7, 9, 11 and 15, the resulting numbers are in proportion. The number to be subtracted is :
#2. A cricketer had a certain average of runs for his 64 innings. In his 65th innings, he is bowled out for no score on his part. This brings down his average by 2 runs. His new average of runs is :
#3. A policeman goes after a thief who has 100 metres start if the policeman runs a kilometre in 8 minute and the thief a km in 10 minute, then the distance covered by the thief before he is over-powered is :
#4. How many numbers between 400 and 800 are divisible by 4, 5 and 6?
#5. A milkman makes 20% profit by selling milk mixed with water at Rs 9 per litre. If the cost price of 1 litre pure milk is Rs 10, then the ratio of milk and water in the said mixture is :
#6. A man borrowed some money from a private organization at 5% simple interest per annum. He lends 50% of this money to another person at 10% compound interest per annum and thereby the man made a profit of Rs 3205 in 4 years. How much did the man borrow?
#7. Two types of tea costing Rs 180 per kg and Rs 280 per kg should be mixed in the ratio so that the mixture obtained was sold at Rs 320 per kg to earn a profit of 20% is
#8. If the ratio of cost price to selling price is 10: 11, then the rate of percent of profit is
#9. A sum of money is divided among A, B, C and D in the proportion of 7 : 6 : 3 : 5. If B gets `270 more than C, then the share of D is :
#10. In a group of students, 70% can speak English and 65% can speak Hindi. If 27% of the students can speak none of the two languages, then what per cent of the group can speak both the languages?
#11. The difference between the value of the number increased by 20% and the value of the number decreased by 25% is 36. Find the number :
#12. The square root of $ \frac{0.324\times0.081\times4.624}{1.5625\times0.0289\times72.9\times64} $
#13. Unit digit in (264)102 + (264)103 is :
#14. A and B can together finish a work in 30 days. They worked at it for 20 days and then B left. The remaining work was done by A alone in 20 more days A alone can finish the work in :
#15. A group of workers can complete a piece of work in 50 days, when they are working individually. On the first day one person works, on the second day another person joins him, on the third day one more person joins them and this process continues till the work is completed. How many approximate days are needed to complete the work?
#16. Two successive discounts of 10% and 5% is given on a bill of Rs 110. Find the net amount of money payable to clear the bill. (Answer to the nearest rupee)
#17. Find the selling price of an article if a shopkeeper allows two successive discounts of 5% each on the marked price of Rs 80
#18. The cost price of 36 books is equal to the selling price of 30 books. The gain percent is :
#19. A shopkeeper sells an article at 15% gain. Had he sold it for Rs 18 more, he would have gained 18%. The cost price (in Rs) of the article is
#20. A man is twice as fast as a woman and a woman is twice as fast as a boy in doing a work. If all of them, a man, a woman and a boy can finish the work in 7 days, in how many days a boy will do it alone?
#21. A table with marked price Rs 1200 was sold to a customer for Rs 1100. Find the rate of discount allowed on the table.
#22. Sunil completes a work in 4 days, whereas Dinesh completes the work in 6 days. Ramesh works $ 1\frac1 2 $ times as fast as Sunil. The three together can complete the work in :
#23. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.
LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013
#24. To gain 8% after allowing a discount of 10%, by what percent cost price should be hiked in the list price?
#25. A man loses Rs 55.50 yearly when the annual rate of interest falls from 11.5% to 10%. His capital (in rupees) is :
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