Quantitative Aptitude Questions with Answers for SSC CGL

Quantitative Aptitude Questions with Answers and Solution for SSC CGL- Mock Test of Maths MCQs set for online practice of upcoming Competitive exams.

Subject : Quantitative Aptitude (Mathematics)
Medium : English
Level : SSC CGL
All type Questions with Solution
As per latest exam pattern and syllabus
Set of 25 Questions – New Questions practice Set in Every Attempt

Results

#1. The ratio of the age of a father to that of his son is 5 : 2. If the product of their ages in years is 1000, then the father’s age (in years) after 10 years will be:

100

#2. The ratio of the ages of A and B at present is 3 : 1. Four years earlier the ratio was 4 : 1. The present age of A is :

48 years

40 years

36 years

32 years

#3. If out of 10 selected students for an examination, 3 were of 20 years age, 4 of 21 and 3 of 22 years, the average age of the group is :

22 year

21 year

21.5 year

20 year

#4. Two trains start at the same time from Aligarh and Delhi and proceed towards each other at the rate of 14 km and 21 km per hour respectively. When they meet, it is found that one train has travelled 70 km more than the other. The distance between the two stations is :

350 km

210 km

300 km

140 km

#5. The average marks of a class of 35 children is 35. The marks of one of the students, who got 35, was incorrectly entered as 65. What is the correct average of the class?

34.14

38.14

28.20

42.21

#6. Three numbers are in the ratio 2 : 3 : 4 and their HCF is 12. The L.C.M of the numbers is

144

192

Let the numbers be 2x, 3x and 4x respectively.
HCF = x = 12
Numbers are : 2 ×12 = 24
3 ×12 = 36, 4 ×12 = 48
LCM of 24, 36, 48
= 2 × 2 × 2 × 3 × 3 × 2 = 144

#7. A tank can be filled by pipe A in 2 hours and pipe B in 6 hours. At 10 a.m., the pipe A was opened. At what time will the tank be filled if pipe B is opened at 11 a.m.?

12.45 a.m.

5 p.m

11.45a.m.

12 p.m.

#8. The average of 15 numbers is 7. If the average of the first 8 numbers be 6.5 and the average of last 8 numbers be 9.5, then the middle number is :

#9. $\sqrt[3]{(333)^3+(333)^3+(334)^3 -3\times333\times333\times334}$ is equal to

#10. 4 boys and 3 girls spent Rs.120 on the average, of which the boys spent Rs.150 on the average. Then the average amount spent by the girls is:

Rs. 80

Rs. 60

Rs. 90

Rs.100

#11. A person buys 100 cups at Rs 10 each. On the way 10 cups are broken. He sells the remaining cups at Rs 11 each. His loss percent is :

$\frac12$ %

1 %

$1\frac12$ %

2 %

#12. The difference between the simple and compound interest on a certain sum of money at 5% rate of interest per annum for 2 years is Rs 15. Then the sum is :

Rs 6500

Rs 8500

Rs 6000

Rs 7000

#13. The difference between the selling prices of an article at a profit of 15% and at a profit of 10% is Rs 10. The cost price of the article is

Rs 100

Rs 120

Rs 150

Rs 200

#14. . If x : y = 3 : 4, then 4x + 5y : 5x− 2y = ?

7 :32

32 : 7

4 : 3

5 : 2

#15. The current ages of Sonali and Monali are in the ratio 5 : 3. Five years from now, their ages will be in the ratio 10 : 7. Then, Monali’ s current age is

5 years

3 years

9 years

15 years

#16. $\frac{4.41\times0.16}{2.1\times 1.6 \times 0.21}$ is simplified to

0.01

0.1

0.01

#17. Find the selling price of an article if a shopkeeper allows two successive discounts of 5% each on the marked price of Rs 80

Rs 70.20

Rs 70.10

Rs 72.00

Rs 72.20

#18. By selling 144 hens Mahesh suffered a loss equal to the selling price of 6 hens. His loss percent is :

4 %

3 %

9 %

$4\frac12$ %

#19. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.

3013

3024

3002

3036

LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013

#20. A worker suffers a 20% cut in his wages. He may regain his original wages by obtaining a rise of

27.5%

25.0%

22.5%

20.0%

#21. The value of $\frac{\sqrt{80}-\sqrt{112}}{\sqrt{45}-\sqrt{63}}$ is

$\frac34$

$1\frac34$

$1\frac13$

$1\frac79$

#22. The average of the largest and smallest 3 digit numbers formed by 0, 2 and 4 would be

312

213

222

303

#23. A train passes a platform 90 metre long in 30 seconds and a man standing on the platform in 15 seconds. The speed of the train is :

12.4 kmph

14.6kmph

18.4kmph

21.6kmph

#24. The Government reduced the price of sugar by 10 per cent. By this a consumer can buy 6.2 kg more sugar for Rs 837. The reduced price per kg of sugar is :

Rs. 12.50

Rs. 13.00

Rs. 13.50

Rs. 14.00

#25. A certain distance is covered by a cyclist at a certain speed. If a jogger covers half the distance in double the time, then the ratio of the speed of the jogger to that of the cyclist is :

1 : 4

4 : 1

1 : 2

2 : 1

FINISH