Quantitative Aptitude Questions with Answers and Solution for SSC CGL- Mock Test of Maths MCQs set for online practice of upcoming Competitive exams.
Subject : Quantitative Aptitude (Mathematics)
Medium : English
Level : SSC CGL
All type Questions with Solution
As per latest exam pattern and syllabus
Set of 25 Questions – New Questions practice Set in Every Attempt
Results
#1. When a particular number is subtracted from each of 7, 9, 11 and 15, the resulting numbers are in proportion. The number to be subtracted is :
#2. Of the three numbers, the first number is twice the second and the second is thrice the third number. If the average of these 3 numbers is 20, then the sum of the largest and the smallest numbers is :
#3. A and B can complete a piece of work in 8 days, B and C can do it in 12 days, C and A can do it in 8 days. A, B and C together can complete it in :
#4. The speed of a boat is 5 km per hour in still water and the speed of the stream is 3 km per hour. If the boat takes 3 hours to go to a place and come back, then the distance of the place is :
#5. In what time will Rs 10000 amount to Rs 13310 at 20% per annum if compounded half yearly?
#6. In selling an article, the single discount equivalent to two successive discounts of 25% and 5% is :
#7. A single discount equivalent to the series of discounts 20%, 10% and 5% is equal to :
#8. The average of 13 results is 70. The average of first seven is 65 and that of the last seven is 75, the seventh result is :
#9. The sum of four consecutive even numbers is 748. The smallest among them is
#10. A shopkeeper allows a discount of 10% on the marked price of a camera. Marked price of the camera, which costs him Rs 600, to make a profit of 20% should be :
#11. In a school $ \frac{1}{10} $ of the boys are same in number as $ \frac14 $ of the girls and $ \frac58 $ of the girls are same in number as $ \frac14 $ of the boys. The ratio of the boys to girls in that school is :
#12. The middle term(s) of the following series 2 + 4 + 6 + … + 198 is
#13. Product of two co-prime numbers is 117. Then their LCM is
HCF of two-prime numbers = 1
Product of numbers = their
LCM = 117
117 = 13 × 9 where 13 & 9 are
co-prime. L.C.M (13,9) = 117
#14. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.
LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013
#15. At what per cent per annum will Rs 3000 amounts to Rs 3993 in 3 years if the interest is compounded annually?
#16. A candidate secured 30% marks in an examination and failed by 6 marks. Another secured 40% marks and got 6 marks more than the bare minimum to pass. The maximum marks are :
#17. 4 boys and 3 girls spent Rs.120 on the average, of which the boys spent Rs.150 on the average. Then the average amount spent by the girls is:
#18. A sells a cycle to B at a profit of 20% and B sells it to C at a loss of 25%. If C bought the cycle for Rs. P, then the cost price of it for A was :
#19. If the compound interest on a certain sum for two years at 12% per annum is Rs 2544, the simple interest on it at the same rate for 2 years will be :
#20. If out of 10 selected students for an examination, 3 were of 20 years age, 4 of 21 and 3 of 22 years, the average age of the group is :
#21. Three numbers are in the ratio 2 : 3 : 4. If the sum of their squares is 1856, then the numbers are
#22. If A and B are the HCF and LCM respectively of two algebraic expressions x and y, and A + B = x + y, then the value of $ A^3+B^3 $ is
#23. Simplify: $ \frac{0.41\times0.41\times0.41+0.69\times0.69\times0.69}{0.41\times0.41-0.41\times 0.69+0.69+0.69} $
#24. The average of 5 consecutive natural numbers is m. If the next three natural numbers are also included, then how much more than m will the average of these 8 numbers be?
#25. LCM of 12 and 16 Prime factorisation of $ 12 = 2^3 $ × 3 = 22 × 3 Prime factorisation of 16 = 2 × 2 × 2 × 2 = 24
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[latex]e^{i pi} 1 = 0[/latex]
[latex]e^{i pi} 1 = 0[/latex]
Thank you so much