Quantitative Aptitude Questions with Answers and Solution for SSC CGL- Mock Test of Maths MCQs set for online practice of upcoming Competitive exams.
Subject : Quantitative Aptitude (Mathematics)
Medium : English
Level : SSC CGL
All type Questions with Solution
As per latest exam pattern and syllabus
Set of 25 Questions – New Questions practice Set in Every Attempt
Results
#1.
If W1 : W2 = 2 : 3 and W1 : W3= 1 : 2 then W2 : W3 is
#2. Three years ago, the average age of a family of 5 members was 17 years. A baby having been born, the average age of the family is the same today. The present age of the baby (in year/s) is :
#3. A car travels at a speed of 60 km/hr and covers a particular distance in one hour. How long will it take for another car to cover the same distance at 40 km/hr?
#4. On multiplying a number by 7, all the digits in the product appear as 3’s. The smallest such number is :
#5. The average of three consecutive odd numbers is 12 more than one third of the first of these numbers. What is the last of the three numbers?
#6. In what time will Rs 10000 amount to Rs 13310 at 20% per annum if compounded half yearly?
#7. If 20 women can lay a road of length 100 m 10 days. Then 10 women can lay the same road of length 50 m in :
#8. Mohan gets 3 marks for each correct sum and loses 2 marks for each wrong sum. He attempts 30 sums and obtains 40 marks. The number of sums solved correctly is
#9. A box contains 280 coins of denomination carrying 1 rupee, 50 paise and 25 paise. The values of each kind of the coins are in the ratio of 8 : 4 : 3. Then the number of 50 paise coins is :
#10. The value of ($ 11111)^2 $ is
#11. The sum of four consecutive even numbers is 748. The smallest among them is
#12. The ratio of the ages of A and B at present is 3 : 1. Four years earlier the ratio was 4 : 1. The present age of A is :
#13. 16 men are able to complete a piece of work in 12 days working 14 hours a day. How long will 28 men, working 12 hours a day, take to complete the work?
#14. (49)15 – 1 is exactly divisible by
#15. The HCF (GCD) of a, b is 12, a, b are positive integers and a > b > 12. The smallest values of (a, b) are respectively
HCF of a and b = 12
Numbers = 12x and 12y where x and y are prime to each other.
a > b > 12
a = 36; b = 24
#16. Three glasses are filled with a mixture of acid and water in equal volume. The ratios of acid and water are 2 : 3, 3 : 4 and 4 : 5 respectively. The contents of these glasses are poured in a large vessel. The ratio of acid and water in the large vessel is :
#17. A man travelled a certain distance by train at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, then the distance was :
#18. The average age of a cricket team of 11 players is the same as it was 3 years back because 3 of the players whose current average age of 33 years were replaced by 3 youngsters. The average age of the newcomers is :
#19. The average per day income of A, B and C is Rs. 450. If the average per day income of A and B be Rs. 400 and that of B and C be Rs. 430, the per day income of B is :
#20. The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train, starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time will they meet?
#21. A sum of Rs 10,000 lent partly at 8% and remaining at 10% per annum. If the yearly interest on the average is 9.2%, the two parts are :
#22. The mean value of 20 observations was found to be 75, but later on it was detected that 97 was misread as 79. Find the correct mean.
#23. If the difference between the compound interest and simple interest on a sum at 5% rate of interest per annum for three years is Rs 36.60, then the sum is :
#24. The wrong number of the sequence 4, 9, 19, 39, 79, 169, 319 is :
#25. The greatest number, which when divide 989 and 1327 leave remainders 5 and 7 respectively, is :
The largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r)
Required number
= HCF of (989 – 5) and (1327 – 7)
= HCF of 984 and 1320 = 24
HCF = 24