Quantitative Aptitude Questions with Answers and Solution for SSC CGL- Mock Test of Maths MCQs set for online practice of upcoming Competitive exams.
Subject : Quantitative Aptitude (Mathematics)
Medium : English
Level : SSC CGL
All type Questions with Solution
As per latest exam pattern and syllabus
Set of 25 Questions – New Questions practice Set in Every Attempt
Results
#1. In two blends of mixed tea, the ratios of Darjeeling and Assam tea are 4 : 7and 2 : 5. The ratio in which these two blends should be mixed to get the ratio of Darjeeling and Assam tea in the new mixture as 6 : 13 is :
#2. In selling an article, the single discount equivalent to two successive discounts of 25% and 5% is :
#3. A can cultivate 
th of a land in 6 days and B can cultivate 
rd of the same land in 10 days. Working together A and B can cultivate 
th of the land in :
#4. If 
, then the value of x is
#5. The least number to be subtracted from 36798 to get a number which is exactly divisible by 78 is
When 36798 is divided by 78, remainder = 60
The least number to be subtracted = 60
#6. The least perfect square, which is divisible by each of 21, 36 and 66 is
#7. 
+
is equal to
#8. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.
LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013
#9. The value of 
is
#10. If Rahim deposited the same amount of Rs x in a bank at the beginning of successive 3 years and the bank pays a simple interest of 5% per annum, then the amount at his credit at the end of 3rd year will be :
#11. A boy and girl together fill a cistern with water. The boy pours 4 litres of water every 3 minutes and the girl pours 3 litres every 4 minutes. How much time will it take to fill 100 litres of water in the cistern?
#12. The average age of 40 students of a class is 15 years. When 10 new students are admitted, the average is increased by 0.2 year. The average age of the new students is :
#13. When 75% of a number is added to 75, the result is the same number. Find the number.
#14. The sum of a natural number and its square equals the product of the first three prime numbers. The number is
#15. A and B together can do a piece of work in 6 days. If A can alone do the work in 18 days, then the number of days required for B to finish the work is :
#16. An old article is available for Rs 12000 at cash payment or is available for Rs 7000 cash payment and a monthly instalment of Rs 630 for 8 months. The rate per cent per annum is :
#17. Alcohol and water in two vessels A and B are in the ratio 5 : 3 and 5 : 4 respectively. In what ratio, the liquids in both the vessels be mixed to obtain a new mixture in vessel C in the ratio 7 : 5 ?
#18. A man bought a watch for 10% discount. If had bought for 20% discount he would have got the watch for Rs 125 less. The marked price of the watch is :
#19. 
part of a tank is full of water. When 30 litres of water is taken out, the tank becomes empty. The capacity of the tank is :
#20. Three numbers which are coprime to one another are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is :
#21. If the difference between the compound interest and simple interest on a sum at 5% rate of interest per annum for three years is Rs 36.60, then the sum is :
#22. The greatest number, that divides 122 and 243 leaving respectively 2 and 3 as remainders, is
Clearly, 122 – 2 = 120 and 243 – 3 = 240 are exactly divisible by the required number.
Required number
= HCF of 120 and 240 = 120
#23. If the ratio of two numbers is 2 : 3 and their LCM is 54, then the sum of the two numbers is
Let the two numbers are 2x and 3x respectively.
According to question,
LCM = 54
x (3×2)=54
x = 9
Numbers = 2x = 2 × 9 = 18 and 3x = 3 × 9 = 27
Sum of the two numbers
= 18 27 = 45
#24. A shopkeeper sold his goods at half the list price and thus lost 20%. If he had sold on the listed price, his gain percentage would be.
#25. A grocery dealer cheats to the extent of 10% while buying as well as selling by using false weight. What is his increase in the profit %?
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