Quantitative Aptitude Questions with Answers and Solution for SSC CGL- Mock Test of Maths MCQs set for online practice of upcoming Competitive exams.
Subject : Quantitative Aptitude (Mathematics)
Medium : English
Level : SSC CGL
All type Questions with Solution
As per latest exam pattern and syllabus
Set of 25 Questions – New Questions practice Set in Every Attempt
Results
#1. In a farm there are cows and hens. If the heads are counted they are 180, if legs are counted they are 420. The number of cows in the farm is :
#2. The average of 15 numbers is 7. If the average of the first 8 numbers be 6.5 and the average of last 8 numbers be 9.5, then the middle number is :
#3. The population of a town increases by 5% every year. If the present population is 9261, the population 3 years ago was :
#4. If the product of two positive numbers is 1575 and their ratio is 7 : 9, then the greatest number is :
#5. The average per day income of A, B and C is Rs. 450. If the average per day income of A and B be Rs. 400 and that of B and C be Rs. 430, the per day income of B is :
#6. The least number which must be added to 1728 to make it a perfect square is :
#7. A manufacturer fixes his selling price at 33% over the cost of production. If the cost of production goes up by 12% and the manufacturer raises his selling price by 10%, his percentage profit is :
#8. The difference between the selling prices of an article at a profit of 15% and at a profit of 10% is Rs 10. The cost price of the article is
#9. The average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. The weight of the new person is :
#10. If the ratio of two numbers is 2 : 3 and their LCM is 54, then the sum of the two numbers is
Let the two numbers are 2x and 3x respectively.
According to question,
LCM = 54
x (3×2)=54
x = 9
Numbers = 2x = 2 × 9 = 18 and 3x = 3 × 9 = 27
Sum of the two numbers
= 18 27 = 45
#11. If a number x is 10% less than another number y and y is 10% more than 125, then x is equal to :
#12. What sum of money must be given as simple interest for six months at 4% per annum in order to earn Rs 150 interest?
#13. A man with $ \frac35 $ of his usual speed reaches the destination $ 2\frac12 $ hours late. Find his usual time to reach the destination .
#14. 1 + 2 + 3 + … + 49 + 50 + 49 + 48 + … + 3 + 2 + 1 is equal to
#15. A man goes downstream with a boat to some destination and returns upstream to his original place in 5 hours. If the speed of the boat in still water and the stream are 10 km/hr and 4 km/hr respectively, then the distance of the destination from the starting place is :
#16. A, B and C can do a piece of work in 30, 20 and 10 days respectively. A is assisted by B on one day and by C on the next day, alternately. How long would the work take to finish?
#17. A store has an offer ‘Buy 4 Get 1 Free’. What is the net percentage of discount?
#18. Instead of multiplying a number by 0.72, a student multiplied it by 7.2. If his answer was 2592 more than the correct answer, then the original number was :
#19. The sum of a pair of positive integer is 336 and their HCF is 21.The number of such possible pairs is
#20. Three numbers which are coprime to one another are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is :
#21. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.
LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013
#22. The average of five numbers is 7. When three new numbers are included, the average of the eight numbers becomes 8.5. The average of three new numbers is :
#23. The ratio of the incomes of A and B as well as B and C is 3 : 2. If one third of A’s income exceeds one fourth of C’s income by Rs.1000, what is B’s income in Rs. ?
#24. A man travelled a certain distance by train at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, then the distance was :
#25. The simplified value of $ \frac{4}{15} \text{ of } \frac58\times 6+15-10 $ is
