SSC CGL

Simplify $ \frac{(x^2 – 9)}{x+3}$ Options a) x – 9b) x + 3c) x – 3d) $ \sqrt{x^2 – 9} $ Solution As per question$ \frac{(x^2 – 9)}{x+3}$ $ \frac{x^2 – 3^2}{x+3}$ $ \frac{(x – 3) (x + 3)}{x+3} = (x – 3)$ Ans is ) x – 3

If $ cosec \theta = \frac 53 $ , then evaluate ($ sec^2 \theta – 1) \times cot^2 \theta \times (1 + cot^2 \theta)$. Optionsa) $ \frac {9}{16}$b) $ \frac {25}{9}$c) $ \frac {25}{16}$d) $ \frac {4}{5}$ Solution As per questionFormula :- $ sec^2 \theta – 1 = tan^2 \theta $$ 1 + cot^2 \theta

The value of cos229o + cos261o is: Optionsa) $ \frac {\sqrt 3}{2}$b) 2c) 0d) 1 Solution As per questioncos229 + cos261ocos229 + (cos 61o)2cos229 + (cos (90 – 29)o)2cos229 + (Sin 29)2 Formula :- $ Sin \theta $ = cos (90 – $ \theta)$cos229 + sin229 = 1Formula :- $ sin^2 \theta + cos^2 \theta

What is the value of sec (t), if tan (t) = $ \frac{1}{3}$ ? Optionsa) $ \frac{ \sqrt3}{3}$b) $ \frac{2 \sqrt2}{3}$c) $ \frac{ \sqrt10}{3}$d) $ \frac{ \sqrt10}{9}$ Solution As per question tan Q = $ \frac {BC}{AC} = \frac 13 $(AB)2 = (AC)2 + (BC)2(AB)2 = (3)2 + (1)2(AB)2 = 9 + 1 = 10AB

The value of sin2 30 – sin2 40 + sin2 45 – sin2 55 – sin2 35 + sin2 45 – sin2 50 + sin2 60 is: Optionsa) 4b) 0c) 1d) 2 Solution As per question sin2 30 – sin2 40 + sin2 45 – sin2 55 – sin2 35 + sin2 45 – sin2

Simplify $ \dfrac{x^3 + 15x^2 + 75x + 125}{x^2 – 25} (x – 5)$. Optionsa) x2 + 5x + 25b) x2 – 25c) x2 + 10x + 25d) x2 + 25 Solution As per question$ \dfrac{x^3 + 15x^2 + 75x + 125}{x^2 – 25} (x – 5)$ $ \dfrac{x^3 + 15x^2 + 75x + 125