Quantitative Aptitude Questions with Answers and Solution for SSC CGL- Mock Test of Maths MCQs set for online practice of upcoming Competitive exams.
Subject : Quantitative Aptitude (Mathematics)
Medium : English
Level : SSC CGL
All type Questions with Solution
As per latest exam pattern and syllabus
Set of 25 Questions – New Questions practice Set in Every Attempt
Results
#1. The ratio of monthly incomes of A and B is 6 : 5 and their monthly expenditures are in the ratio 4 : 3. If each of them saves Rs. 400 per month, then find the sum of their monthly incomes.
#2. A man bought an old type writer for Rs 1200 and spent Rs 200 on its repair. He sold it for Rs 1680. His profit per cent is :
#3. A person can row 
km an hour in still water and he finds that it takes him twice as long to row up as to row down the river. The speed of the stream is :
#4. The average of 5 consecutive natural numbers is m. If the next three natural numbers are also included, then how much more than m will the average of these 8 numbers be?
#5. A worker suffers a 20% cut in his wages. He may regain his original wages by obtaining a rise of
#6. In a school having roll strength 286, the ratio of boys and girls is 8 : 5. If 22 more girls get admitted into the school, the ratio of boys and girls become
#7. If one-ninth of a certain number exceeds its one-tenth by 4, the number is :
#8. Arvind spends 75% of his income and saves the rest. His income is increased by 20% and he increases his expenditure by 10%. Then the increase in savings in percentage is
#9. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.
LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013
#10. A bag contains Rs. 90 coins in the denominations of 50 paise, 25 paise and 10 paise. If coins of 50 paise, 25 paise and 10 paise are in the ratio of 2 : 3 : 5, then the number of 25 paise coins in the bag is
#11. A person can row a distance of one km upstream in ten minutes and downstream in four minutes. What is the speed of the stream?
#12. 
is equal to
#13. (49)15 – 1 is exactly divisible by
#14. A candidate secured 30% marks in an examination and failed by 6 marks. Another secured 40% marks and got 6 marks more than the bare minimum to pass. The maximum marks are :
#15. If 2 + x
=
then the simplest value of x is :
#16. The value of 
#17. A builder borrows Rs 2550 which is to be paid back with compound interest at the rate of 4% per annum by the end of 2 years in two equal yearly instalments. How much will each instalment be?
#18. The average of 20 numbers is calculated as 35. It is discovered later, that while calculating the average, one number, namely 85, was read as 45. The correct average is :
#19. 
is simplified to
#20. In selling an article, the single discount equivalent to two successive discounts of 25% and 5% is :
#21. A man, a woman and a boy together finish a piece of work in 6 days. If a man and a woman can do the same work in 10 and 24 days respectively then the number of days taken by a boy to finish the work is :
#22. By how much does 
exceed 
?
#23. Two numbers are less than a third number by 30% and 37% respectively. How much per cent is the second number less than the first?
#24. A and B can do a work in 12 days, B and C in 15 days and C and A in 20 days. If A, B and C work together, they will complete the work in
#25. Three numbers are in the ratio 1 : 2 : 3 and their HCF is 12. The numbers are
Numbers = x , 2 x and 3 x (let)
Their HCF = x = 12
Numbers = 12, 24 and 36
Thank you so much