Quantitative Aptitude Questions with answers and Solutions for SSC CPO- SI in CPMF Exam. Maths MCQs Mock Test for free online practice of SI CAPF Exam.
Practice Set : Mathematics (Quantitative Aptitude)
Questions : 50
Medium : English
Level : SSC CPO SI Exam
All Type and topic MCQs – Solved by short tricks
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#1. A and B can do a work in 12 days, B and C in 15 days and C and A in 20 days. If A, B and C work together, they will complete the work in

#2. Find the value of
52 + 62 +72 … + 102

#3. Between two consecutive years my income are in the ratio of 2 : 3 and expenses are in the ratio of 5 : 9. If my income in the second year is `45,000 and my expenses in the first year is ` 25,000 my total savings for the two years is :

#4. On selling 17 balls at Rs 720, there is a loss equal to the cost price of 5 balls. The cost price (in Rs) of a ball is

#5. The missing number of the sequence 0, 2, 8, 18,__, 50 is :

#6. If the ratio of cost price to selling price is 10: 11, then the rate of percent of profit is

#7. The greatest value among the fractions

#8. The list price of a clock is Rs 160. A customer buys it for Rs 122.40 after two successive discounts. If first discount is 10%, the second is ?

#9. The least number, that must be added to 1720 so as to obtain a perfect cube is :

#10. If
, then the value of x is

#11. The fourth proportional to 0.12, 0.21, 8 is :

#12. The value of is

#13. 2 men and 1 woman together can complete a piece of work in 14 days, while 4 women and 2 men together can do it in 8 days. If a man gets Rs 600 per day, how much should a woman get per day?

#14. A man rows down a river 15 km in 3 hours with the stream and returns in
hours. The rate at which he swims 26 km downstream is :

#15. Three numbers which are coprime to one another are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is :

#16. A manufacturer fixes his selling price at 33% over the cost of production. If the cost of production goes up by 12% and the manufacturer raises his selling price by 10%, his percentage profit is :

#17.
is equal to

#18. The HCF and LCM of two numbers are 21 and 84 respectively. If the ratio the two numbers is 1 : 4, then the larger of the two numbers is
HCF of numbers = 21
Numbers = 21x and 21y
Where x and y are prime to each other.
Ratio of numbers = 1 : 4
Larger number = 21 × 4 = 84
#19. What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7 ?
LCM of 9, 10 and 15 = 90
The multiple of 90 are also divisible by 9, 10 or 15.
21 × 90 = 1890 will be divisible by them.
Now, 1897 will be the number
that will give remainder 7.
Required number = 1936 – 1897 = 39
#20. The average of 20 numbers is calculated as 35. It is discovered later, that while calculating the average, one number, namely 85, was read as 45. The correct average is :

#21. If a = 4011 and b = 3989, then the value of ab = ?

#22. Which of the following number is the greatest of all?

#23. A sum of Rs 1600 gives a simple interest of Rs 252 in 2 years and 3 months. The rate of interest per annum is :

#24. The HCF of two numbers is 8. Which one of the following can never be their LCM ?
HCF of two numbers is 8.This means 8 is a factor common to both the numbers. LCM is common multiple for the two numbers, it is divisible by the two numbers. So, the required answer = 60
#25.
+
is equal to

#26. If the price of petrol be raised by 20%, then the percentage by which a car owner must reduce his consumption so as not to increase his expenditure on petrol is :

#27. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.
LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013
#28. The number 96 – 11 when divided by 8 would leave a remainder of

#29. The average of 30 numbers is 12. The average of the first 20 of them is 11 and that of the next 9 is 10. The last number is :
Explanation: Last number :
= 30 × 12-20 × 11 − 9 × 10
= 360 − 220 − 90
= 360 − 310 = 50
#30. The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train, starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time will they meet?

#31. Ravi buys an article with a discount of 25% on its marked price. He makes a profit of 10% by selling it at Rs 660. The marked price of the article was :

#32. The digit in unit’s place of the number (1570)2 + (1571)2 + (1572)2 + (1573)2 is :

#33. A grocery dealer cheats to the extent of 10% while buying as well as selling by using false weight. What is his increase in the profit %?

#34. The sum of a natural number and its square equals the product of the first three prime numbers. The number is

#35. The mean value of 20 observations was found to be 75, but later on it was detected that 97 was misread as 79. Find the correct mean.

#36. An old article is available for Rs 12000 at cash payment or is available for Rs 7000 cash payment and a monthly instalment of Rs 630 for 8 months. The rate per cent per annum is :

#37. A boat goes 12 km downstream and comes back to the starting point in 3 hours. If the speed of the current is 3 km/hr, then the speed (in km/hr) of the boat in still water is :

#38. When 75% of a number is added to 75, the result is the same number. Find the number.

#39.
is equal to

#40. Two types of tea costing Rs 180 per kg and Rs 280 per kg should be mixed in the ratio so that the mixture obtained was sold at Rs 320 per kg to earn a profit of 20% is

#41. A thief steals a car at 1.30 p.m. and drives it off at 40 km/hr. The theft is discovered at 2 p.m. and the owner sets off in another car at 50 km/hr. He will overtake the thief at :

#42. If 20% of A = 50% of B, then what per cent of A is B?

#43. The product of two 2–digit numbers is 2160 and their HCF is 12. The numbers are

#44. If the price of a commodity is increased by 50%, by what fraction must its consumption be reduced so as to keep the same expenditure on its consumption?

#45. If Rahim deposited the same amount of Rs x in a bank at the beginning of successive 3 years and the bank pays a simple interest of 5% per annum, then the amount at his credit at the end of 3rd year will be :

#46. A candidate secured 30% marks in an examination and failed by 6 marks. Another secured 40% marks and got 6 marks more than the bare minimum to pass. The maximum marks are :

#47. The total discount on Rs 1860 due after a certain time at 5% is Rs 60. Find the time after which it is due :

#48. Three glasses are filled with a mixture of acid and water in equal volume. The ratios of acid and water are 2 : 3, 3 : 4 and 4 : 5 respectively. The contents of these glasses are poured in a large vessel. The ratio of acid and water in the large vessel is :

#49. Sunil completes a work in 4 days, whereas Dinesh completes the work in 6 days. Ramesh works
times as fast as Sunil. The three together can complete the work in :

#50. Find the unit digit in the product
(4387)245 × (621)72
