Quantitative Aptitude Questions for SSC CPO

Quantitative Aptitude Questions with answers and Solutions for SSC CPO- SI in CPMF Exam. Maths MCQs Mock Test for free online practice of SI CAPF Exam.

Practice Set : Mathematics (Quantitative Aptitude)
Questions : 50
Medium : English
Level : SSC CPO SI Exam
All Type and topic MCQs – Solved by short tricks
Immediate display of Answer and Solution
New Practice of 50 Questions in every attempt

 

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#1. Six numbers are arranged in decreasing order. The average of the first five numbers is 30 and the average of the last five numbers is 25. The difference of the first and the last numbers is :

#2. The ratio of cost price and selling price is 5 : 4, the loss percent is :

#3. In an examination there are three subjects of 100 marks each. A student scores 60% in the first subject and 80% in the second subject. He scored 70% in aggregate. His percentage of marks in the third subject is :

#4. A train passes two bridges of lengths 500 m and 250 m in 100 seconds and 60 seconds respectively. The length of the train is :

#5. If I purchased 11 books for Rs 100 and sold 10 books for Rs 110, the percentage of profit per book sold is :

#6. If a = 4011 and b = 3989, then the value of ab = ?

#7. A number is first decreased by 20%. The decreased number is then increased by 20%. The resulting number is less than the original number by 20. Then the original number is

#8. The average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. The weight of the new person is :

#9. Two boats A and B start towards each other from two places, which is 108 km apart. Speed of the boat A and B in still water are 12 km/hr and 15 km/hr respectively. If A proceeds down and B up the stream, they will meet after how many hours?

#10. If the average weight of 6 students is 50 kg; that of 2 students is 51 kg and that of 2 other students is 55 kg; then the average weight of all the students is :

#11. On multiplying a number by 7, all the digits in the product appear as 3’s. The smallest such number is :

#12. A vessel contains 20 litres of acid. 4 litres of acid is taken out of the vessel and replaced by the same quantity of water. The next 4 litres of the mixture are withdrawn and again the vessel is filled with the same quantity of acid left in the vessel with the quantity of acid initially in the vessel is :

#13. A sum of Rs 3200 invested at 10% p.a. compounded quarterly amounts to Rs 3362. Compute the time period

#14. The mean of 20 items is 55. If two items such as 45 and 30 are removed, the new mean of the remaining items is :

#15. A tap can fill a cistern in 40 minutes and a second tap can empty the filled cistern in 60 minutes. By mistake without closing the second tap, the first tap was opened. In how many minutes will the empty cistern be filled?

#16. By walking at $ \frac34 $ of his usual speed, a man reaches his office 20 minutes later than his usual time. The usual time taken by him to reach his office is :

#17. If a number x is 10% less than another number y and y is 10% more than 125, then x is equal to :

#18. A group of workers can complete a piece of work in 50 days, when they are working individually. On the first day one person works, on the second day another person joins him, on the third day one more person joins them and this process continues till the work is completed. How many approximate days are needed to complete the work?

#19. A man rows down a river 15 km in 3 hours with the stream and returns in $ 7\frac1 2 $ hours. The rate at which he swims 26 km downstream is :

#20. A person buys 100 cups at Rs 10 each. On the way 10 cups are broken. He sells the remaining cups at Rs 11 each. His loss percent is :

#21. A group of 75 men are employed to lay down a railway line in 3 months. Due to certain emergency conditions, the work was to be finished in 18 days. How many more men should be employed to complete the work in the desired time ?

#22. $ \frac34 $ part of a tank is full of water. When 30 litres of water is taken out, the tank becomes empty. The capacity of the tank is :

#23. If a boy walks from his house to school at the rate of 4 km per hour, he reaches the school 10 minutes earlier than the scheduled time. However, if he walks at the rate of 3 km per hour, then he reaches 10 minutes late. Find the distance of his school from his house :

#24. A double bed is marked at Rs 7500. The shopkeeper allows successive discounts of 8%, 5% and 2% on it. What is the net selling price?

#25. A manufacturer fixes his selling price at 33% over the cost of production. If the cost of production goes up by 12% and the manufacturer raises his selling price by 10%, his percentage profit is :

#26. If X = $ (0.25)^{\frac12} $, Y = $ (0.4)^2 $, Z =$ (0.216)^{\frac13} $, then

#27. Simplify: $ \frac{0.41\times0.41\times0.41+0.69\times0.69\times0.69}{0.41\times0.41-0.41\times 0.69+0.69+0.69} $

#28. A tank has two pipes. The first pipe can fill it in 4 hours and the second can empty it in 16 hours. If two pipes be opened together at a time, then the tank will be filled in :

#29. The total number of prime factors in $ 4^{10}\times{7}^3\times{16}^2\times11\times{10}^2 $ is

#30. Find the value of

52 + 62 +72 … + 102

#31. if$ \frac{1120}{\sqrt P} $ =80, then P is equal to

#32. A man, a woman and a boy can together complete a piece of work in 3 days. If a man alone can do it in 6 days and a boy alone in 18 days, how long will a woman alone take to complete the work?

#33. The HCF of two numbers is 8. Which one of the following can never be their LCM ?

HCF of two numbers is 8.This means 8 is a factor common to both the numbers. LCM is common multiple for the two numbers, it is divisible by the two numbers. So, the required answer = 60

#34. A student multiplied a number by $ \frac35 $ instead of $ \frac53 $ . What is the percentage error in the calculation?

#35. Pipe A can fill an empty tank in 6 hours and pipe B in 8 hours. If both the pipes are opened and after 2 hours pipe A is closed, how much time B will take to fill the remaining tank?

#36. The rational number between $ \frac12 $ and $ \frac35 $ is

#37. Arrange $ \frac45,\frac78,\frac67,\frac56 $ in the ascending order.

#38. The average of the largest and smallest 3 digit numbers formed by 0, 2 and 4 would be

#39. A sum of money placed at compound interest doubles itself in 4 years. In how many years will it amount to four times itself ?

#40. The compound interest on a certain sum of money at a certain rate for 2 years is Rs 40.80 and the simple interest on the same sum is Rs 40 at the same rate and for the same time. The rate of interest is :

#41. The average per day income of A, B and C is Rs. 450. If the average per day income of A and B be Rs. 400 and that of B and C be Rs. 430, the per day income of B is :

#42. The total discount on Rs 1860 due after a certain time at 5% is Rs 60. Find the time after which it is due :

#43. How many numbers between 400 and 800 are divisible by 4, 5 and 6?

#44. By selling 144 hens Mahesh suffered a loss equal to the selling price of 6 hens. His loss percent is :

#45. The value of is $ 1-\frac{1}{1+\frac{2}{3 + \frac{4}{5}}} $

#46. Two numbers are in ratio 5 : 8. If their difference is 48, then the smaller number is :

#47. A sum of money is paid back in two annual instalments of Rs 17640 each, allowing 5% compound interest compounded annually. The sum borrowed was :

#48. If $ (125)^{2/3}\times (625)^{1/4} = 5^{x} $, then the value of x is

#49. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.

LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013

#50. In what time will Rs 10000 amount to Rs 13310 at 20% per annum if compounded half yearly?

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