Quantitative Aptitude Questions with answers and Solutions for SSC CPO- SI in CPMF Exam. Maths MCQs Mock Test for free online practice of SI CAPF Exam.
Practice Set : Mathematics (Quantitative Aptitude)
Questions : 50
Medium : English
Level : SSC CPO SI Exam
All Type and topic MCQs – Solved by short tricks
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New Practice of 50 Questions in every attempt
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#1. The total number of prime factors in $ 4^{10}\times{7}^3\times{16}^2\times11\times{10}^2 $ is
#2. A person can row a distance of one km upstream in ten minutes and downstream in four minutes. What is the speed of the stream?
#3. An item when sold for Rs 1690 earned 30% profit on the cost price. Then the cost price is :
#4. A policeman goes after a thief who has 100 metres start if the policeman runs a kilometre in 8 minute and the thief a km in 10 minute, then the distance covered by the thief before he is over-powered is :
#5. If x : y = 3 : 4 and y : z = 3 : 4, then $ \frac {x+y+z} {3z} $ is equal to :
#6. If 2 + x$ \sqrt3 $ =$ \frac{1}{2+\sqrt3} $ then the simplest value of x is :
#7. The ratio of cost price and selling price is 5 : 4, the loss percent is :
#8. HCF of $ \frac {2}{3} , \frac{4}{5} and \frac{6}{7} $ is
#9. $ \sqrt[3]{(333)^3+(333)^3+(334)^3 -3\times333\times333\times334} $ is equal to
#10. If the product of first 50 positive consecutive integers be divisible by $ 7^n $ , where n is an integer, then the largest possible value of n is :
#11. Three numbers are in the ratio 2 : 3 : 4 and their HCF is 12. The L.C.M of the numbers is
Let the numbers be 2x, 3x and 4x respectively.
HCF = x = 12
Numbers are : 2 ×12 = 24
3 ×12 = 36, 4 ×12 = 48
LCM of 24, 36, 48
= 2 × 2 × 2 × 3 × 3 × 2 = 144
#12. The rational number between $ \frac12 $ and $ \frac35 $ is
#13. Find the largest number of four digits such that on dividing by 15,18, 21 and 24 the remainders are 11, 14, 17 and 20 respectively.
#14. If a = 4011 and b = 3989, then the value of ab = ?
#15. A certain distance is covered by a cyclist at a certain speed. If a jogger covers half the distance in double the time, then the ratio of the speed of the jogger to that of the cyclist is :
#16. Product of two co-prime numbers is 117. Then their LCM is
HCF of two-prime numbers = 1
Product of numbers = their
LCM = 117
117 = 13 × 9 where 13 & 9 are
co-prime. L.C.M (13,9) = 117
#17. If A and B are in the ratio 4 : 5 and the difference of their squares is 81, what is the value of A?
#18. By selling an article for Rs 69, there is a loss of 8%, when the article is sold for Rs 78, the gain or loss per cent is :
#19. Of the three numbers, the first number is twice the second and the second is thrice the third number. If the average of these 3 numbers is 20, then the sum of the largest and the smallest numbers is :
#20. Two pipes A and B can separately fill a tank in 2 hours and 3 hours respectively. If both the pipes are opened simultaneously in the empty tank, then the tank will be filled in :
#21. . A train is running at 36 km/hr. If it crosses a pole in 25 seconds, then its length is :
#22. A sum of money placed at compound interest doubles itself in 4 years. In how many years will it amount to four times itself ?
#23. Two numbers are in the ratio 1 : 3 If their sum is 240, then their difference is :
#24. A student multiplied a number by $ \frac35 $ instead of $ \frac53 $ . What is the percentage error in the calculation?
#25. The fourth proportional to 0.12, 0.21, 8 is :
#26. The simplification of $ \frac18+\frac{1}{8^2}+\frac{1}{8^3}+\frac{1}{8^4}+\frac{1}{8^5} $up to three places of decimals yields
#27. The difference between the compound interest and simple interest on a certain sum for 2 years at 10% per annum is 300. Find the sum.
#28. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.
LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013
#29. Find the unit digit in the product
(4387)245 × (621)72
#30. In selling an article, the single discount equivalent to two successive discounts of 25% and 5% is :
#31. The greatest number, which when divide 989 and 1327 leave remainders 5 and 7 respectively, is :
The largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r)
Required number
= HCF of (989 – 5) and (1327 – 7)
= HCF of 984 and 1320 = 24
HCF = 24
#32. A sum of money at simple interest triples itself in 15 years. It will become 5 times of itself in :
#33. The average of 20 numbers is calculated as 35. It is discovered later, that while calculating the average, one number, namely 85, was read as 45. The correct average is :
#34. If the cost price of 10 articles equals selling price of 9 articles, the gain or loss percent will be :
#35. 5 – [4 – (3 – (3 – 3 – 6))] is equal to
#36. Two numbers are in the ratio 2: 3. If 20% of the smaller number added to 20 is equal to the sum of 10% of the larger number and 25, then the smaller number is :
#37. The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs.12,000 and the average salary of the rest is Rs.6000. The total number of workers in the workshop is :
#38. If 80 persons can finish a work within 16 days by working 6 hours a day, the number of hours a day, should 64 persons work to finish that very job within 15 days is :
#39. If a boy walks from his house to school at the rate of 4 km per hour, he reaches the school 10 minutes earlier than the scheduled time. However, if he walks at the rate of 3 km per hour, then he reaches 10 minutes late. Find the distance of his school from his house :
#40. Find the sum of the first five terms of the following series.$ \frac{1}{1\times4}+\frac{1}{4\times7}+\frac{1}{7\times10} $ +………+…….
#41. The sum of a pair of positive integer is 336 and their HCF is 21.The number of such possible pairs is
#42. If a number x is 10% less than another number y and y is 10% more than 125, then x is equal to :
#43. A person deposited a sum of 6000 in a bank at 5% per annum simple interest. Another person deposited 5000 at 8% per annum compound interest. After two years, the difference of their interests will be :
#44. A number is first decreased by 20%. The decreased number is then increased by 20%. The resulting number is less than the original number by 20. Then the original number is
#45. If the average of eight consecutive even numbers be 93, then the greatest number among them is :
#46. The least number that should be added to 2055, so that the sum is exactly divisible by 27 is :
#47. The average per day income of A, B and C is Rs. 450. If the average per day income of A and B be Rs. 400 and that of B and C be Rs. 430, the per day income of B is :
#48. A man and a boy received Rs 800 as wages for 5 days for the work they did together. The man’s efficiency in the work was three times that of the boy. What are the daily wages of the boy ?
#49. A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, then how far is the place?
#50. A bag contains Rs. 90 coins in the denominations of 50 paise, 25 paise and 10 paise. If coins of 50 paise, 25 paise and 10 paise are in the ratio of 2 : 3 : 5, then the number of 25 paise coins in the bag is
