Quantitative Aptitude Questions with answers and Solutions for SSC CPO- SI in CPMF Exam. Maths MCQs Mock Test for free online practice of SI CAPF Exam.
Practice Set : Mathematics (Quantitative Aptitude)
Questions : 50
Medium : English
Level : SSC CPO SI Exam
All Type and topic MCQs – Solved by short tricks
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#1. A takes three times as long as B and C together to do a job. B takes four times as long as A and C together to do the work. If all the three, working together can complete the job in 24 days, then the number of days, A alone will take to finish the job is
#2. Find the value of $ \frac{2}{1+\frac{1}{1-\frac{1}{2}}} \times\frac{3}{\frac56 \text{of} \frac{3}{2} \div 1\frac14} $
#3. The quotient when $ 10^{100} $ is divided by $ 5^{75} $ is
#4. If in a sale, the discount given on a saree is equal to one-fourth the marked price and the loss due to this discount is 15%, then the ratio of the cost price to the selling price is :
#5. Sarita and Julie start walking from the same place in the opposite directions. If Julie walks at a speed of $ 2\frac12 $ km/hr and Sarita at a speed of 2 km/hr, then in how much time will they be 18 km apart?
#6. The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight (in kg) of B is :
#7. A and B can complete a piece of work in 8 days, B and C can do it in 12 days, C and A can do it in 8 days. A, B and C together can complete it in :
#8. To gain 8% after allowing a discount of 10%, by what percent cost price should be hiked in the list price?
#9. Find the least multiple of 23, which when divided by 18, 21 and 24 leaves the remainder 7, 10 and 13 respectively.
LCM of 18, 21 and 24
LCM = 2 × 3 × 3 × 7 × 4 = 504
Now compare the divisors with their respective remainders. We observe that in all the cases the remainder is just 11 less than their respective divisor. So the number can be given by 504 K – 11 Where K is a positive integer
Since 23 × 21 = 483
We can write 504 K – 11
= (483 21) K – 11, = 483 K (21K – 11)
483 K is multiple of 23, since 483 is divisible by 23.
So, for (504K – 11) to be multiple of 23, the remainder (21K – 11) must be divisible by 23.
Put the value of K = 1, 2, 3, 4, 5,6, ….. and so on successively.
We find that the minimum value of K for which (21K – 11) is divisible by 23. is 6, (21 × 6 – 11)
= 115 which is divisible by 23.
Therefore, the required least number
= 504 × 6 – 11 = 3013
#10. A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
#11. Water tax is increased by 20% but its consumption is decreased by 20%. Then the increase or decrease in the expenditure of the money is :
#12. The average marks of a class of 35 children is 35. The marks of one of the students, who got 35, was incorrectly entered as 65. What is the correct average of the class?
#13. A table with marked price Rs 1200 was sold to a customer for Rs 1100. Find the rate of discount allowed on the table.
#14. The speed of two trains is in the ratio of 6 : 7. If the second train runs 364 km in 4 hours, then the speed of first train is ?
#15. A trader marked the price of a commodity so as to include a profit of 25%, but allowed a discount of 16% on the market price. His actual profit will be :
#16. The difference between the selling prices of an article at a profit of 15% and at a profit of 10% is Rs 10. The cost price of the article is
#17. When 75% of a number is added to 75, the result is the same number. Find the number.
#18. At some rate of simple interest, A lent Rs 6000 to B for 2 years and Rs 1500 to C for 4 years and received Rs 900 as interest from both of them together. The rate of interest per annum was :
#19. The population of a town increases by 5% every year. If the present population is 9261, the population 3 years ago was :
#20. The monthly salaries of A, B and C are in the ratio of 2 : 3 : 5. If C’s monthly salary is Rs.12,000 more than that of A, then B’s annual salary is :
#21. Find the sum of the first five terms of the following series.$ \frac{1}{1\times4}+\frac{1}{4\times7}+\frac{1}{7\times10} $ +………+…….
#22. On selling an article for Rs 651, there is a loss of 7%. The cost price of that article is :
#23. Three years ago, the average age of a family of 5 members was 17 years. A baby having been born, the average age of the family is the same today. The present age of the baby (in year/s) is :
#24. Divide Rs. 7500 among A, B and C such that A’s share to B’s share is in the ratio of 5 : 2 and B’s share to C’s share is in the ratio 7 : 13. How much will B receive?
#25. A 200 metre long train is running at a speed of 72 km/hr. How long will it take to cross 800 metre long bridge?
#26. A sum of Rs 400 amounts to Rs 480 in 4 years. What will it amount to if the rate of interest is increased by 2%?
#27. If one-ninth of a certain number exceeds its one-tenth by 4, the number is :
#28. The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is :
L.C.M. of 4, 6, 8, 12 and 16 = 48
Required number = 48 2 = 50
#29. The simple interest on a sum after 4 years is $ \frac15 $ of the sum. The rate of interest per annum is :
#30. If the product of first 50 positive consecutive integers be divisible by $ 7^n $ , where n is an integer, then the largest possible value of n is :
#31. The mean value of 20 observations was found to be 75, but later on it was detected that 97 was misread as 79. Find the correct mean.
#32. The simplified value of $ (0.2)^3\times 200 \div 2000\: \text{of} \:(0.2)^2 $ is
#33. A and B can together finish a work in 30 days. They worked at it for 20 days and then B left. The remaining work was done by A alone in 20 more days A alone can finish the work in :
#34. A shopkeeper sold his goods at half the list price and thus lost 20%. If he had sold on the listed price, his gain percentage would be.
#35. The greatest number, which when divide 989 and 1327 leave remainders 5 and 7 respectively, is :
The largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r)
Required number
= HCF of (989 – 5) and (1327 – 7)
= HCF of 984 and 1320 = 24
HCF = 24
#36. A number is first decreased by 20%. The decreased number is then increased by 20%. The resulting number is less than the original number by 20. Then the original number is
#37. The sum 5 + 6 + 7 + 8 + … + 19 is equal to
#38. A tank has two pipes. The first pipe can fill it in 4 hours and the second can empty it in 16 hours. If two pipes be opened together at a time, then the tank will be filled in :
#39. Three numbers are in the ratio 2 : 3 : 4. If the sum of their squares is 1856, then the numbers are
#40. If the discount is equal to one fifth of the marked price and the loss is half the discount, then the percentage of loss is :
#41. The least number that should be added to 2055, so that the sum is exactly divisible by 27 is :
#42. Find the value of
52 + 62 +72 … + 102
#43. If the square of the sum of two numbers is equal to 4 times of their product, then the ratio of these numbers is :
#44. if $ (1101)^2 $ = 12122101, then find the value of $ \sqrt{121.2201} $
#45. A reduction of 25% in the price of rice enables a person to buy 10 kg more rice for Rs.600. The reduced per kg price of rice
#46. If a = 4011 and b = 3989, then the value of ab = ?
#47. Two pipes A and B can separately fill a cistern in 60 minutes and 75 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is filled in 50 minutes. In how much time the third pipe alone can empty the cistern?
#48. The least perfect square, which is divisible by each of 21, 36 and 66 is
#49. Instead of multiplying a number by 0.72, a student multiplied it by 7.2. If his answer was 2592 more than the correct answer, then the original number was :
#50. The total discount on Rs 1860 due after a certain time at 5% is Rs 60. Find the time after which it is due :
