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#1. सरल करें: \(\frac{0.41\times0.41\times0.41+0.69\times0.69\times0.69}{0.41\times0.41-0.41\times 0.69+0.69+0.69}\)
#2. वह बड़ी से बड़ी संख्या, जिससे 122 और 243 को भाग देने पर क्रमश: 2 और 3 शेष बचता है, वह है
Clearly, 122 – 2 = 120 and 243 – 3 = 240 are exactly divisible by the required number.
Required number
= HCF of 120 and 240 = 120